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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (d+d+2+2)/(d*d+4*d+4+16) = 1/(d+1) .
    Question type: Equation
    Solution:Original question:
     ( d + d + 2 + 2) ÷ ( d d + 4 d + 4 + 16) = 1 ÷ ( d + 1)
     Multiply both sides of the equation by:( d d + 4 d + 4 + 16) ,  ( d + 1)
     ( d + d + 2 + 2)( d + 1) = 1( d d + 4 d + 4 + 16)
    Remove a bracket on the left of the equation::
      d ( d + 1) + d ( d + 1) + 2( d + 1) + 2( d + 1) = 1( d d + 4 d + 4 + 16)
    Remove a bracket on the right of the equation::
      d ( d + 1) + d ( d + 1) + 2( d + 1) + 2( d + 1) = 1 d d + 1 × 4 d + 1 × 4 + 1 × 16
    The equation is reduced to :
      d ( d + 1) + d ( d + 1) + 2( d + 1) + 2( d + 1) = 1 d d + 4 d + 4 + 16
    The equation is reduced to :
      d ( d + 1) + d ( d + 1) + 2( d + 1) + 2( d + 1) = 1 d d + 4 d + 20
    Remove a bracket on the left of the equation:
      d d + d × 1 + d ( d + 1) + 2( d + 1) + 2( d + 1) = 1 d d + 4 d + 20
    Remove a bracket on the left of the equation:
      d d + 1 d + d d + d × 1 + 2( d + 1) + 2( d + 1) = 1 d d + 4 d + 20
    The equation is reduced to :
      d d + 2 d + d d + 2( d + 1) + 2( d + 1) = 1 d d + 4 d + 20
    Remove a bracket on the left of the equation:
      d d + 2 d + d d + 2 d + 2 × 1 + 2( d + 1) = 1 d d + 4 d + 20
    The equation is reduced to :
      d d + 2 d + d d + 2 d + 2 + 2( d + 1) = 1 d d + 4 d + 20
    The equation is reduced to :
      d d + 4 d + d d + 2 + 2( d + 1) = 1 d d + 4 d + 20
    Remove a bracket on the left of the equation:
      d d + 4 d + d d + 2 + 2 d + 2 × 1 = 1 d d + 4 d + 20
    The equation is reduced to :
      d d + 4 d + d d + 2 + 2 d + 2 = 1 d d + 4 d + 20
    The equation is reduced to :
      d d + 6 d + d d + 4 = 1 d d + 4 d + 20

    The solution of the equation:
        d1≈-5.123106 , keep 6 decimal places
        d2≈3.123106 , keep 6 decimal places
    
    There are 2 solution(s).


解程的详细方法请参阅:《方程的解法》



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