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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 6 questions will be solved this time.Among them
           ☆6 equations

[ 1/6 Equation]
    Work: Find the solution of equation i1 = i2+i6 .
    Question type: Equation
    Solution:Original question:
      i × 1 = i × 2 + i × 6
     Right side of the equation = 8 i
    The equation is transformed into :
     1 i = 8 i
    i.e.
      i = 8 i
    This is the solution of the equation.
    This is the solution of the equation.

[ 2/6 Equation]
    Work: Find the solution of equation i2 = i4+i3 .
    Question type: Equation
    Solution:Original question:
      i × 2 = i × 4 + i × 3
     Right side of the equation = 7 i
    The equation is transformed into :
     2 i = 7 i

    The coefficient of the unknown number is reduced to 1 :
      i = 7 ÷ 2
        = 7 ×
1
2

    We obtained :
      i =
7
2
    This is the solution of the equation.

    Convert the result to decimal form :
      i = 3.5

[ 3/6 Equation]
    Work: Find the solution of equation i5 = i4+i6 .
    Question type: Equation
    Solution:Original question:
      i × 5 = i × 4 + i × 6
     Right side of the equation = 10 i
    The equation is transformed into :
     5 i = 10 i

    The coefficient of the unknown number is reduced to 1 :
      i = 10 ÷ 5
        = 10 ×
1
5
        = 2 × 1

    We obtained :
      i = 2
    This is the solution of the equation.

[ 4/6 Equation]
    Work: Find the solution of equation 2i6+40 = 8i4+10i2 .
    Question type: Equation
    Solution:Original question:
     2 i × 6 + 40 = 8 i × 4 + 10 i × 2
     Left side of the equation = 12 i + 40
    The equation is transformed into :
     12 i + 40 = 8 i × 4 + 10 i × 2
     Right side of the equation = 32 i + 20 i
                                               = 52 i
    The equation is transformed into :
     12 i + 40 = 52 i

    Transposition :
     12 i 52 i = - 40

    Combine the items on the left of the equation:
      - 40 i = - 40

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     40 = 40 i

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     40 i = 40

    The coefficient of the unknown number is reduced to 1 :
      i = 40 ÷ 40
        = 40 ×
1
40
        = 1 × 1

    We obtained :
      i = 1
    This is the solution of the equation.

[ 5/6 Equation]
    Work: Find the solution of equation 2i6+40+4i3+20+10i1 = 8i4 .
    Question type: Equation
    Solution:Original question:
     2 i × 6 + 40 + 4 i × 3 + 20 + 10 i × 1 = 8 i × 4
     Left side of the equation = 12 i + 40 + 12 i + 20 + 10 i
                                             = 34 i + 60
    The equation is transformed into :
     34 i + 60 = 8 i × 4
     Right side of the equation = 32 i
    The equation is transformed into :
     34 i + 60 = 32 i

    Transposition :
     34 i 32 i = - 60

    Combine the items on the left of the equation:
     2 i = - 60

    The coefficient of the unknown number is reduced to 1 :
      i = - 60 ÷ 2
        = - 60 ×
1
2
        = - 30 × 1

    We obtained :
      i = - 30
    This is the solution of the equation.

[ 6/6 Equation]
    Work: Find the solution of equation 4i3+20 = 8i5+8i4 .
    Question type: Equation
    Solution:Original question:
     4 i × 3 + 20 = 8 i × 5 + 8 i × 4
     Left side of the equation = 12 i + 20
    The equation is transformed into :
     12 i + 20 = 8 i × 5 + 8 i × 4
     Right side of the equation = 40 i + 32 i
                                               = 72 i
    The equation is transformed into :
     12 i + 20 = 72 i

    Transposition :
     12 i 72 i = - 20

    Combine the items on the left of the equation:
      - 60 i = - 20

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     20 = 60 i

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     60 i = 20

    The coefficient of the unknown number is reduced to 1 :
      i = 20 ÷ 60
        = 20 ×
1
60
        = 1 ×
1
3

    We obtained :
      i =
1
3
    This is the solution of the equation.

    Convert the result to decimal form :
      i = 0.333333



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