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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (4.3-0.24÷1000(x+1000))(1000-x) = (0.698-0.29÷1000(x+1000))(x-100) .
    Question type: Equation
    Solution:Original question:
     (
43
10
−
6
25
÷ 1000 × ( x + 1000))(1000 − x ) = (
349
500
−
29
100
÷ 1000 × ( x + 1000))( x − 100)
    Remove the bracket on the left of the equation:
     Left side of the equation =
43
10
(1000 − x ) −
6
25
÷ 1000 × ( x + 1000)(1000 − x )
                                             =
43
10
(1000 − x ) −
3
12500
( x + 1000)(1000 − x )
                                             =
43
10
× 1000 −
43
10
x −
3
12500
( x + 1000)(1000 − x )
                                             = 4300 −
43
10
x −
3
12500
( x + 1000)(1000 − x )
                                             = 4300 −
43
10
x −
3
12500
x (1000 − x ) −
3
12500
× 1000(1000 − x )
                                             = 4300 −
43
10
x −
3
12500
x (1000 − x ) −
6
25
(1000 − x )
                                             = 4300 −
43
10
x −
3
12500
x × 1000 +
3
12500
x x −
6
25
(1000 − x )
                                             = 4300 −
43
10
x −
6
25
x +
3
12500
x x −
6
25
(1000 − x )
                                             = 4300 −
227
50
x +
3
12500
x x −
6
25
(1000 − x )
                                             = 4300 −
227
50
x +
3
12500
x x −
6
25
× 1000 +
6
25
x
                                             = 4300 −
227
50
x +
3
12500
x x − 240 +
6
25
x
                                             = 4060 −
43
10
x +
3
12500
x x
    The equation is transformed into :
     4060 −
43
10
x +
3
12500
x x = (
349
500
−
29
100
÷ 1000 × ( x + 1000))( x − 100)
    Remove the bracket on the right of the equation:
     Right side of the equation =
349
500
( x − 100) −
29
100
÷ 1000 × ( x + 1000)( x − 100)
                                               =
349
500
( x − 100) −
29
100000
( x + 1000)( x − 100)
                                               =
349
500
x −
349
500
× 100 −
29
100000
( x + 1000)( x − 100)
                                               =
349
500
x −
349
5
−
29
100000
( x + 1000)( x − 100)
                                               =
349
500
x −
349
5
−
29
100000
x ( x − 100) −
29
100000
× 1000( x − 100)
                                               =
349
500
x −
349
5
−
29
100000
x ( x − 100) −
29
100
( x − 100)
                                               =
349
500
x −
349
5
−
29
100000
x x +
29
100000
x × 100 −
29
100
( x − 100)
                                               =
349
500
x −
349
5
−
29
100000
x x +
29
1000
x −
29
100
( x − 100)
                                               =
727
1000
x −
349
5
−
29
100000
x x −
29
100
( x − 100)
                                               =
727
1000
x −
349
5
−
29
100000
x x −
29
100
x +
29
100
× 100
                                               =
727
1000
x −
349
5
−
29
100000
x x −
29
100
x + 29
                                               =
437
1000
x −
204
5
−
29
100000
x x

    
        x≈971.237007 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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