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Enter the mathematical formula directly and click the "Next" button to get the calculation answer.
It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （16.5x+x）X2 = 65 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
After the equation is converted into a general formula, it is converted into:
( √7x +√13 )( √7x - √13 )=0
From
√7x +√13 = 0
√7x - √13 = 0
it is concluded that:：
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （16.5x+x）X2 = 65 .
Question type: Equation
Solution:Original question:
| ( | 33 2 | x | + | x | ) | x | × | 2 | = | 65 |
| Left side of the equation = | 33 2 | x | x | × | 2 | + | x | x | × | 2 |
| = | 33 | x | x | + | x | x | × | 2 |
| 33 | x | x | + | x | x | × | 2 | = | 65 |
After the equation is converted into a general formula, it is converted into:
( √7x +√13 )( √7x - √13 )=0
From
√7x +√13 = 0
√7x - √13 = 0
it is concluded that:：
| x1= | - | √13 √7 |
| x2= | √13 √7 |
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》