detailed information: The input equation set is:
 | | | | | x | + | | | 27 5 | y | + | | | 144 5 | z | = | | | 3 10 | | (1) |
| | | x | + | | | 28 5 | y | + | | | 159 5 | z | = | | - | 9 5 | | (2) |
| | | x | + | | | 19 5 | y | + | | | 74 5 | z | = | | - | 9 5 | | (3) |
| Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
 | | | | | x | + | | | 27 5 | y | + | | | 144 5 | z | = | | | 3 10 | | (1) |
| | | | x | + | | | 19 5 | y | + | | | 74 5 | z | = | | - | 9 5 | | (3) |
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Subtract both sides of equation (1) from both sides of equation (3) ,the equations are reduced to:
 | | | | | x | + | | | 27 5 | y | + | | | 144 5 | z | = | | | 3 10 | | (1) |
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Multiply both sides of equation (2) by 8, the equation can be obtained: , then add the two sides of equation (4) to both sides of equation (3), the equations are reduced to:
 | | | | | x | + | | | 27 5 | y | + | | | 144 5 | z | = | | | 3 10 | | (1) |
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Multiply both sides of equation (3) by 3 Divide both sides of equation (3) by 10, get the equation:, then subtract both sides of equation (5) from both sides of equation (2), get the equation:
 | | | | | x | + | | | 27 5 | y | + | | | 144 5 | z | = | | | 3 10 | | (1) |
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Multiply both sides of equation (3) by 72 Divide both sides of equation (3) by 25, get the equation:, then subtract both sides of equation (6) from both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 27, get the equation:, then subtract both sides of equation (7) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |