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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (3*b^2+2*b-4)^2-6*(b^2-2)*(2+b)^2 = 0 .
    Question type: Equation
    Solution:
    After the equation is converted into a general formula, there is a common factor:
    ( √3b +√8 )( √3b - √8 )
    From
        √3b +√8 = 0
        √3b - √8 = 0
    it is concluded that:：

b1=

-

√8 √3

b2=

√8 √3

    Solutions that cannot be obtained by factorization:
        b₃≈-1.464102 , keep 6 decimal places
        b₄≈5.464102 , keep 6 decimal places    
    There are 4 solution(s).

解程的详细方法请参阅：《方程的解法》

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