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==equ==
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==LiAl==
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On line Solution of Monovariate Equation
> The history of univariate equation calculation
(26.293+x)×2.45=26.293+71.778-x
x+1/x-5/2
A -1000- (A-1000)/1.06 × 0.06 - (A-1000)/1.06 × 0.06 ×12% -(A+1000)× 0.03% - (A -1000- (A-1000)/1.06 × 0.06 - (A-1000)/1.06 × 0.06 ×12% -(A+1000)× 0.03% )× 15%=1000×3%
A -1000- (A-1000)/1.06 × 0.06 - (A-1000)/1.06 × 0.06 ×12% -(A+1000)× 0.03% - (A -1000- (A-1000)/1.06 × 0.06 - (A-1000)/1.06 × 0.06 ×12% -(A+1000)× 0.03% )× 15%=1000×3%
A - A/1.06 × 0.06 - A/1.06 × 0.06 ×12% -(A+1000)× 0.03% - { (A-A/1.06 × 0.06 -A/1.06 × 0.06 ×12%-(A+1000)× 0.03%)× 15%}=A×3%
A - A/1.06 × 0.06 - A/1.06 × 0.06 ×12% -(A+1000)× 0.03% - {(A-A/1.06 × 0.06 -A/1.06 × 0.06 ×12%-(A+1000)× 0.03%)× 15%}=A×1.03
A - A/1.06 × 0.06 - A/1.06 × 0.06 ×12% -(A+1000)× 0.03% - { (A-A/1.06 × 0.06 -A/1.06 × 0.06 ×12%-(A+1000)× 0.03%)× 15%}=A×(1+3%)
3(X+5)=4X+5
A - A/1.06 × 0.06 - A/1.06 × 0.06 ×12% -(A+1000)× 0.03% - { (A-A/1.06 × 0.06 -A/1.06 × 0.06 ×12%-(A+1000)× 0.03%)× 15%}=A×3%
x+1/x=37/6
5a+20+50=202
5a=80
4a=20
3.9538=((28.02*0.639(x+0.1))/(1+0.639(x+0.1))*((100-6.66-1.14)/100)*(1/(1+0.31*1.14))+((0.76(x+0.1))/(1.3*0.101325))
(1+x)^x
(1+x)^x
x×x=0.833(0.1-x)
x×x=0.0833(0.1-x)
x^3-12x-16=0
(1+x)/(7+x)=3/5
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