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current location:Solving equations online > On line Solution of Monovariate Equation > The history of univariate equation calculation
    15*x^2+4/3*x^3=300
    0.31=0.2x×(1/0.012)×(0.2x/(0.2+2x))^(2/3)
    (1+10*t)*e-10t=0.1
    (1+10*t)*e-10t=0.9
    (1+10*t)*e-10=0.9
    (1+10*t)*e-10*t=0.9
    x^3-6x-6=0
    (A-57185029.55)*0.5/100+58841547.47=A
    (A-57185029.55)*0.5/100+58839077.28=A
    X/1.13*0.13=11620.71
    50-5P=-10+5P
    40+4p=-p+50
    p-(p^(10/13))*(0.101325^(3/13))=16.6865*103.8/1000*0.3/10
    4in2
    y= e ( 13.02470713) / ( 1 + e ( 13.02470713 ) )
    y= e ( 15.90764848) / ( 1 + e ( 15.90764848 ) )
    y= e ( 0.061634057) / ( 1 + e ( 0.061634057 ) )
    y= e ( 6.569113235) / ( 1 + e ( 6.569113235 ) )
    y= e ( -9.365100647) / ( 1 + e ( -9.365100647 ) )
    2X-(10-X) = 6

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