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current location:Solving equations online > On line Solution of Monovariate Equation > The history of univariate equation calculation
    e^x=0.09
    1b×3b
    n(n+2)=25. 774
    0=1400Q-(400+550Q)-84Q
    n(n+2)=29. 699
    0=1400Q-(400+500Q)-84Q
    0=1400Q-(400+500Q)-1400Q*0.06
    0=1400Q-((400+500Q))-1400Q*0.06
    0=1400Q-((400+500Q)+331.569+25+0+0)-1400Q*0.06
    n(n+2)=121. 35
    n(n+2)=3. 324
    3141=103000*x*(1+x)^36/((1+x)^36-1)
    3050=100000*x*(1+x)^36/((1+x)^36-1)
    2030=70000*x*((1+x)^36)/[((1+x)^36)-1]
    3141=103000*x*((1+x)^36)/[((1+x)^36)-1]
    2030=70000*x*(1+x)^36/((1+x)^36-1)
    2030=70000*x*(1+x)^36/((1+x)^36)
    x^2+ln(-x)=0
    x^3-10x^2-17x+20=0
    x*3-10x*2-17x+20=0

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