0.2+0.2*8*0.2*(cos(x)+1)+0.3*16*0.2*(cos(2*x)+1)=1
    0.3+0.3*8*0.5*(cos(x)+1)+0.3*16*0.5*(cos(2*x)+1)=1
    √（10^2÷0.78^2÷（（0.04）*0.78^2+1）÷（（0.25）*0.78^2+1））=1÷a
    0.2+0.2*8*0.5*(cos(x)+1)+0.2*16*0.5*(cos(2*x)+1)=1
    0.2+0.2*8*(cos(x)+1)+0.2*16*(cos(2*x)+1)=1
    0.3+0.3*8*(cos(x)+1)+0.3*16*(cos(2*x)+1)=1
    0.5+0.5*8*(cos(x)+1)+0.5*16*(cos(2*x)+1)=1
    0.3+0.3*0.5*8*(cos(x)+1)+0.3*0.5*16*(cos(2*x)+1)=1
    -90-arctan（0.2*w）-arctan（0.5*w）=-120
    X-X*0.065-(X+10000000)*0.0003=10000000
    √（10^2÷w^2÷（（0.04）*w^2+1）÷（（0.25）*w^2+1））=1
    √（10^2÷w^2÷（（0.04）*w^2+1）÷（（0.25）*w^2+1））=-6.82
    X-X*0.065+(X+10000000)*0.0003=10000000
    20*lg√（200^2÷w^2÷（（0.01）*w^2+1））=-6.82
    0.2+1.6*cos(x)+2.4*cos(2*x)=1
    0.3+2.4*cos(x)+4.8*cos(2*x)=1
    √（200^2÷w^2÷（（0.01）*w^2+1））=1
    （800+X-12168.93）*(1-25%)+5213.15 = 5634.18
    20*lg√（16^2÷w^2÷（w^2+1）÷（（0.01^2）*w^2+1）=-6.82
    20*lg√（16^2*（1+（4.39÷3×w）^2）÷w^2÷（w^2+1）÷（（0.01^2）*w^2+1）÷（1+（w÷3）^2））=-6.82

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