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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1.5032 = 1/((0.303/4)+(0.0253/x)+(0.6717/0.95)) .
    Question type: Equation
    Solution:Original question:
     
1879
1250
= 1 ÷ ((
303
1000
÷ 4) + (
253
10000
÷ x ) + (
6717
10000
÷
19
20
))
     Multiply both sides of the equation by:((
303
1000
÷ 4) + (
253
10000
÷ x ) + (
6717
10000
÷
19
20
))
     
1879
1250
((
303
1000
÷ 4) + (
253
10000
÷ x ) + (
6717
10000
÷
19
20
)) = 1
    Remove a bracket on the left of the equation::
     
1879
1250
(
303
1000
÷ 4) +
1879
1250
(
253
10000
÷ x ) +
1879
1250
(
6717
10000
÷
19
20
) = 1
    Remove a bracket on the left of the equation:
     
1879
1250
×
303
1000
÷ 4 +
1879
1250
(
253
10000
÷ x ) +
1879
1250
(
6717
10000
÷
19
20
) = 1
    The equation is reduced to :
     
569337
5000000
+
1879
1250
(
253
10000
÷ x ) +
1879
1250
(
6717
10000
÷
19
20
) = 1
    Remove a bracket on the left of the equation:
     
569337
5000000
+
1879
1250
×
253
10000
÷ x +
1879
1250
(
6717
10000
÷
19
20
) = 1
    The equation is reduced to :
     
569337
5000000
+
475387
12500000
÷ x +
1879
1250
(
6717
10000
÷
19
20
) = 1
     Multiply both sides of the equation by: x
     
569337
5000000
x +
475387
12500000
+
1879
1250
(
6717
10000
÷
19
20
) x = 1 x
    Remove a bracket on the left of the equation:
     
569337
5000000
x +
475387
12500000
+
1879
1250
×
6717
10000
÷
19
20
× x = 1 x
    The equation is reduced to :
     
569337
5000000
x +
475387
12500000
+
12621243
11875000
x = 1 x
    This equation has no real solution!


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