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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/(d+1) = 2/(d-2)+1/(d-5) .
    Question type: Equation
    Solution:Original question:
     1 ÷ ( d + 1) = 2 ÷ ( d 2) + 1 ÷ ( d 5)
     Multiply both sides of the equation by:( d + 1) ,  ( d 2)
     1( d 2) = 2( d + 1) + 1 ÷ ( d 5) × ( d + 1)( d 2)
    Remove a bracket on the left of the equation::
     1 d 1 × 2 = 2( d + 1) + 1 ÷ ( d 5) × ( d + 1)( d 2)
    Remove a bracket on the right of the equation::
     1 d 1 × 2 = 2 d + 2 × 1 + 1 ÷ ( d 5) × ( d + 1)( d 2)
    The equation is reduced to :
     1 d 2 = 2 d + 2 + 1 ÷ ( d 5) × ( d + 1)( d 2)
     Multiply both sides of the equation by:( d 5)
     1 d ( d 5)2( d 5) = 2 d ( d 5) + 2( d 5) + 1( d + 1)( d 2)
    Remove a bracket on the left of the equation:
     1 d d 1 d × 52( d 5) = 2 d ( d 5) + 2( d 5) + 1( d + 1)( d 2)
    Remove a bracket on the right of the equation::
     1 d d 1 d × 52( d 5) = 2 d d 2 d × 5 + 2( d 5) + 1( d + 1)( d 2)
    The equation is reduced to :
     1 d d 5 d 2( d 5) = 2 d d 10 d + 2( d 5) + 1( d + 1)( d 2)
    Remove a bracket on the left of the equation:
     1 d d 5 d 2 d + 2 × 5 = 2 d d 10 d + 2( d 5) + 1( d + 1)( d 2)
    Remove a bracket on the right of the equation::
     1 d d 5 d 2 d + 2 × 5 = 2 d d 10 d + 2 d 2 × 5 + 1( d + 1)( d 2)
    The equation is reduced to :
     1 d d 5 d 2 d + 10 = 2 d d 10 d + 2 d 10 + 1( d + 1)( d 2)
    The equation is reduced to :
     1 d d 7 d + 10 = 2 d d 8 d 10 + 1( d + 1)( d 2)
    Remove a bracket on the right of the equation::
     1 d d 7 d + 10 = 2 d d 8 d 10 + 1 d ( d 2) + 1 × 1( d 2)
    The equation is reduced to :
     1 d d 7 d + 10 = 2 d d 8 d 10 + 1 d ( d 2) + 1( d 2)
    Remove a bracket on the right of the equation::
     1 d d 7 d + 10 = 2 d d 8 d 10 + 1 d d 1 d × 2
    The equation is reduced to :
     1 d d 7 d + 10 = 2 d d 8 d 10 + 1 d d 2 d + 1
    The equation is reduced to :
     1 d d 7 d + 10 = 2 d d 10 d 10 + 1 d d + 1( d 2)
    Remove a bracket on the right of the equation::
     1 d d 7 d + 10 = 2 d d 10 d 10 + 1 d d + 1 d 1
    The equation is reduced to :
     1 d d 7 d + 10 = 2 d d 10 d 10 + 1 d d + 1 d 2
    The equation is reduced to :
     1 d d 7 d + 10 = 2 d d 9 d 12 + 1 d d

    The solution of the equation:
        d1≈-2.854102 , keep 6 decimal places
        d2≈3.854102 , keep 6 decimal places
    
    There are 2 solution(s).


解程的详细方法请参阅:《方程的解法》



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