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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 12.88*8000*x*(1177.56-1464+x/2)+12.88*(5000-8000)*160*(1177.56-1464+160/2) = 330*6792*1177.56-330*4024*(-0.1044) .
    Question type: Equation
    Solution:Original question:
     
322
25
× 8000 x (
29439
25
1464 + x ÷ 2) +
322
25
(50008000) × 160(
29439
25
1464 + 160 ÷ 2) = 330 × 6792 ×
29439
25
330 × 4024( -
261
2500
)
     Left side of the equation = 103040 x (
29439
25
1464 + x ÷ 2) +
10304
5
(50008000)(
29439
25
1464 + 160 ÷ 2)
    The equation is transformed into :
     103040 x (
29439
25
1464 + x ÷ 2) +
10304
5
(50008000)(
29439
25
1464 + 160 ÷ 2) = 330 × 6792 ×
29439
25
330 × 4024( -
261
2500
)
    Remove the bracket on the left of the equation:
     Left side of the equation = 103040 x ×
29439
25
103040 x × 1464 + 103040 x x ÷ 2 +
10304
5
(50008000)
                                             =
606678912
5
x 150850560 x + 51520 x x +
10304
5
(50008000)(
29439
25
1464 + 160 ÷ 2)
                                             = -
147573888
5
x + 51520 x x +
10304
5
(50008000)(
29439
25
1464 + 160 ÷ 2)
                                             = -
147573888
5
x + 51520 x x +
10304
5
× 5000(
29439
25
1464 + 160 ÷ 2)
10304
5
× 8000(
29439
25
1464 + 160 ÷ 2)
                                             = -
147573888
5
x + 51520 x x + 10304000(
29439
25
1464 + 160 ÷ 2)16486400(
29439
25
1464 + 160 ÷ 2)
                                             = -
147573888
5
x + 51520 x x + 10304000 ×
29439
25
10304000 × 1464 + 10304000 × 160 ÷ 2

    
        x≈-42.964174 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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