Overview: 4 questions will be solved this time.Among them
☆4 equations
[ 1/4 Equation]
Work: Find the solution of equation (128-X)*(1-20%) = X-20 .
Question type: Equation
Solution:Original question:| | ( | 128 | − | X | ) | ( | 1 | − | 20 100 | ) | = | X | − | 20 |
Remove the bracket on the left of the equation:
| Left side of the equation = | 128 | ( | 1 | − | 20 100 | ) | − | X | ( | 1 | − | 20 100 | ) |
| = | 128 | × | 1 | − | 128 | × | 20 100 | − | X | ( | 1 | − | 20 100 | ) |
| = | 128 | − | 128 5 | − | X | ( | 1 | − | 20 100 | ) |
| = | 512 5 | − | X | × | 1 | + | X | × | 20 100 |
The equation is transformed into :
Transposition :
Combine the items on the left of the equation:
Combine the items on the right of the equation:
By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
[ 2/4 Equation]
Work: Find the solution of equation 102.4-0.8X = X-20 .
Question type: Equation
Solution:Original question:
Transposition :
Combine the items on the left of the equation:
Combine the items on the right of the equation:
By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
[ 3/4 Equation]
Work: Find the solution of equation 1.8X = 122.4 .
Question type: Equation
Solution:Original question:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
[ 4/4 Equation]
Work: Find the solution of equation X = 68 .
Question type: Equation
Solution:Original question: This is the solution of the equation.
This is the solution of the equation.
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