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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/d+1/d+1/(d+6) = 1/(d+4) .
    Question type: Equation
    Solution:Original question:
     1 ÷ d + 1 ÷ d + 1 ÷ ( d + 6) = 1 ÷ ( d + 4)
     Multiply both sides of the equation by: d  ,  ( d + 4)
     1( d + 4) + 1 ÷ 1 × 1( d + 4) + 1 ÷ ( d + 6) × d ( d + 4) = 1 d
    Remove a bracket on the left of the equation::
     1 d + 1 × 4 + 1 ÷ 1 × 1( d + 4) + 1 ÷ ( d + 6) × d ( d + 4) = 1 d
    The equation is reduced to :
     1 d + 4 + 1( d + 4) + 1 ÷ ( d + 6) × d ( d + 4) = 1 d
     Multiply both sides of the equation by:( d + 6)
     1 d ( d + 6) + 4( d + 6) + 1( d + 4)( d + 6) + 1 d ( d + 4) = 1 d ( d + 6)
    Remove a bracket on the left of the equation:
     1 d d + 1 d × 6 + 4( d + 6) + 1( d + 4)( d + 6) + 1 = 1 d ( d + 6)
    Remove a bracket on the right of the equation::
     1 d d + 1 d × 6 + 4( d + 6) + 1( d + 4)( d + 6) + 1 = 1 d d + 1 d × 6
    The equation is reduced to :
     1 d d + 6 d + 4( d + 6) + 1( d + 4)( d + 6) + 1 d = 1 d d + 6 d
    Remove a bracket on the left of the equation:
     1 d d + 6 d + 4 d + 4 × 6 + 1( d + 4)( d + 6) = 1 d d + 6 d
    The equation is reduced to :
     1 d d + 6 d + 4 d + 24 + 1( d + 4)( d + 6) + 1 = 1 d d + 6 d
    The equation is reduced to :
     1 d d + 10 d + 24 + 1( d + 4)( d + 6) + 1 d ( d + 4) = 1 d d + 6 d
    Remove a bracket on the left of the equation:
     1 d d + 10 d + 24 + 1 d ( d + 6) + 1 × 4( d + 6) = 1 d d + 6 d
    The equation is reduced to :
     1 d d + 10 d + 24 + 1 d ( d + 6) + 4( d + 6) + 1 = 1 d d + 6 d
    Remove a bracket on the left of the equation:
     1 d d + 10 d + 24 + 1 d d + 1 d × 6 = 1 d d + 6 d
    The equation is reduced to :
     1 d d + 10 d + 24 + 1 d d + 6 d + 4 = 1 d d + 6 d
    The equation is reduced to :
     1 d d + 16 d + 24 + 1 d d + 4( d + 6) + 1 = 1 d d + 6 d
    Remove a bracket on the left of the equation:
     1 d d + 16 d + 24 + 1 d d + 4 d + 4 = 1 d d + 6 d
    The equation is reduced to :
     1 d d + 16 d + 24 + 1 d d + 4 d + 24 = 1 d d + 6 d
    The equation is reduced to :
     1 d d + 20 d + 48 + 1 d d + 1 d ( d + 4) = 1 d d + 6 d
    Remove a bracket on the left of the equation:
     1 d d + 20 d + 48 + 1 d d + 1 d d = 1 d d + 6 d
    The equation is reduced to :
     1 d d + 20 d + 48 + 1 d d + 1 d d = 1 d d + 6 d
    The equation is reduced to :
     1 d d + 24 d + 48 + 1 d d + 1 d d = 1 d d + 6 d
    
    There are 0 solution(s).


解程的详细方法请参阅:《方程的解法》



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