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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation a+1/a = 0.5*(1+a*a)*[1+(1/a)*(1/a)] .
    Question type: Equation
    Solution:Original question:
      a + 1 ÷ a =
1
2
(1 + a a )(1 + (1 ÷ a )(1 ÷ a ))
     Multiply both sides of the equation by: a
      a a + 1 =
1
2
(1 + a a )(1 + (1 ÷ a )(1 ÷ a )) a
    Remove a bracket on the right of the equation::
      a a + 1 =
1
2
× 1(1 + (1 ÷ a )(1 ÷ a )) a +
1
2
a a (1 + (1 ÷ a )(1 ÷ a )) a
    The equation is reduced to :
      a a + 1 =
1
2
(1 + (1 ÷ a )(1 ÷ a )) a +
1
2
a a (1 + (1 ÷ a )(1 ÷ a )) a
    Remove a bracket on the right of the equation::
      a a + 1 =
1
2
× 1 a +
1
2
(1 ÷ a )(1 ÷ a ) a +
1
2
a a (1 + (1 ÷ a )(1 ÷ a )) a
    The equation is reduced to :
      a a + 1 =
1
2
a +
1
2
(1 ÷ a )(1 ÷ a ) a +
1
2
a a (1 + (1 ÷ a )(1 ÷ a )) a
    Remove a bracket on the right of the equation::
      a a + 1 =
1
2
a +
1
2
× 1 ÷ 1 × (1 ÷ a ) × 1 +
1
2
a a (1 + (1 ÷ a )(1 ÷ a )) a
    The equation is reduced to :
      a a + 1 =
1
2
a +
1
2
(1 ÷ a ) +
1
2
a a (1 + (1 ÷ a )(1 ÷ a )) a
    Remove a bracket on the right of the equation::
      a a + 1 =
1
2
a +
1
2
× 1 ÷ a +
1
2
a a (1 + (1 ÷ a )(1 ÷ a )) a
    The equation is reduced to :
      a a + 1 =
1
2
a +
1
2
÷ a +
1
2
a a (1 + (1 ÷ a )(1 ÷ a )) a
     Multiply both sides of the equation by: a
      a a a + 1 a =
1
2
a a +
1
2
+
1
2
a a (1 + (1 ÷ a )(1 ÷ a )) a a
    Remove a bracket on the right of the equation::
      a a a + 1 a =
1
2
a a +
1
2
+
1
2
a a × 1 a a +
1
2
a
    The equation is reduced to :
      a a a + 1 a =
1
2
a a +
1
2
+
1
2
a a a a +
1
2
a a
    Remove a bracket on the right of the equation::
      a a a + 1 a =
1
2
a a +
1
2
+
1
2
a a a a +
1
2
× 1 × 1
    The equation is reduced to :
      a a a + 1 a =
1
2
a a +
1
2
+
1
2
a a a a +
1
2
(1 ÷ 1) a
    Remove a bracket on the right of the equation::
      a a a + 1 a =
1
2
a a +
1
2
+
1
2
a a a a +
1
2
× 1 ÷ 1
    The equation is reduced to :
      a a a + 1 a =
1
2
a a +
1
2
+
1
2
a a a a +
1
2
a a

    After the equation is converted into a general formula, it is converted into:
    ( a - 1 )( a - 1 )=0
    From
        a - 1 = 0
        a - 1 = 0

    it is concluded that::
        a1=1
        a2=1
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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