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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/d+1/(d+1) = 1/(d+0.5) .
    Question type: Equation
    Solution:Original question:
     1 ÷ d + 1 ÷ ( d + 1) = 1 ÷ ( d +
1
2
)
     Multiply both sides of the equation by: d  ,  ( d +
1
2
)
     1( d +
1
2
) + 1 ÷ ( d + 1) × d ( d +
1
2
) = 1 d
    Remove a bracket on the left of the equation::
     1 d + 1 ×
1
2
+ 1 ÷ ( d + 1) × d ( d +
1
2
) = 1 d
    The equation is reduced to :
     1 d +
1
2
+ 1 ÷ ( d + 1) × d ( d +
1
2
) = 1 d
     Multiply both sides of the equation by:( d + 1)
     1 d ( d + 1) +
1
2
( d + 1) + 1 d ( d +
1
2
) = 1 d ( d + 1)
    Remove a bracket on the left of the equation:
     1 d d + 1 d × 1 +
1
2
( d + 1) + 1 d ( d +
1
2
) = 1 d ( d + 1)
    Remove a bracket on the right of the equation::
     1 d d + 1 d × 1 +
1
2
( d + 1) + 1 d ( d +
1
2
) = 1 d d + 1 d × 1
    The equation is reduced to :
     1 d d + 1 d +
1
2
( d + 1) + 1 d ( d +
1
2
) = 1 d d + 1 d
    Remove a bracket on the left of the equation:
     1 d d + 1 d +
1
2
d +
1
2
× 1 + 1 d ( d +
1
2
) = 1 d d + 1 d
    The equation is reduced to :
     1 d d + 1 d +
1
2
d +
1
2
+ 1 d ( d +
1
2
) = 1 d d + 1 d
    The equation is reduced to :
     1 d d +
3
2
d +
1
2
+ 1 d ( d +
1
2
) = 1 d d + 1 d
    Remove a bracket on the left of the equation:
     1 d d +
3
2
d +
1
2
+ 1 d d + 1 d ×
1
2
= 1 d d + 1 d
    The equation is reduced to :
     1 d d +
3
2
d +
1
2
+ 1 d d +
1
2
d = 1 d d + 1 d
    The equation is reduced to :
     1 d d + 2 d +
1
2
+ 1 d d = 1 d d + 1 d
    
    There are 0 solution(s).


解程的详细方法请参阅:《方程的解法》



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