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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (1-x)(-3-x)(1-x)-16+4(1-x)+4(1-x)-4(-3-x) = 0 .
    Question type: Equation
    Solution:Original question:
     (1 x )( - 3 x )(1 x )16 + 4(1 x ) + 4(1 x )4( - 3 x ) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = 1( - 3 x )(1 x ) x ( - 3 x )(1 x )16 + 4(1 x ) + 4(1 x )4
                                             = - 1 × 3(1 x )1 x (1 x ) x ( - 3 x )(1 x )16 + 4(1 x )
                                             = - 3(1 x )1 x (1 x ) x ( - 3 x )(1 x )16 + 4(1 x ) + 4
                                             = - 3 × 1 + 3 x 1 x (1 x ) x ( - 3 x )(1 x )16 + 4
                                             = - 3 + 3 x 1 x (1 x ) x ( - 3 x )(1 x )16 + 4(1 x )
                                             = - 19 + 3 x 1 x (1 x ) x ( - 3 x )(1 x ) + 4(1 x ) + 4
                                             = - 19 + 3 x 1 x × 1 + 1 x x x ( - 3 x )(1 x )
                                             = - 19 + 3 x 1 x + 1 x x x ( - 3 x )(1 x ) + 4
                                             = - 19 + 2 x + 1 x x x ( - 3 x )(1 x ) + 4(1 x ) + 4
                                             = - 19 + 2 x + 1 x x + x × 3(1 x ) + x x (1 x )
                                             = - 19 + 2 x + 1 x x + x × 3 × 1 x × 3 x
                                             = - 19 + 2 x + 1 x x + x × 3 x × 3 x + x
                                             = - 19 + 5 x + 1 x x x × 3 x + x x (1 x )
                                             = - 19 + 5 x + 1 x x x × 3 x + x x × 1
                                             = - 19 + 5 x + 1 x x x × 3 x + x x × 1
                                             = - 19 + 5 x + 1 x x x × 3 x + x x × 1
                                             = - 15 + 1 x + 1 x x x × 3 x + x x × 1
                                             = - 15 + 1 x + 1 x x x × 3 x + x x × 1
                                             = - 15 + 1 x + 1 x x x × 3 x + x x × 1
                                             = - 113 x + 1 x x x × 3 x + x x × 1
                                             = - 113 x + 1 x x x × 3 x + x x × 1
                                             = - 113 x + 1 x x x × 3 x + x x × 1
                                             = 1 + 1 x + 1 x x x × 3 x + x x × 1
    The equation is transformed into :
     1 + 1 x + 1 x x x × 3 x + x x × 1 = 0

    After the equation is converted into a general formula, it is converted into:
    ( x + 1 )( x + 1 )( x - 1 )=0
    From
        x + 1 = 0
        x + 1 = 0
        x - 1 = 0

    it is concluded that::
        x1=-1
        x2=-1
        x3=1
    
    There are 3 solution(s).


解程的详细方法请参阅:《方程的解法》



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