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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (1+20%)x*90%+[(2200-x)+15%(2200-x)]*90% = 2200+131 .
    Question type: Equation
    Solution:Original question:
     (1 +
20
100
) x ×
90
100
+ ((2200 x ) +
15
100
(2200 x )) ×
90
100
= 2200 + 131
    Remove the bracket on the left of the equation:
     Left side of the equation = 1 x ×
90
100
+
20
100
x ×
90
100
+ ((2200 x ) +
15
100
(2200 x )) ×
90
100
                                             =
9
10
x +
9
50
x + ((2200 x ) +
15
100
(2200 x )) ×
90
100
                                             =
27
25
x + ((2200 x ) +
15
100
(2200 x )) ×
90
100
                                             =
27
25
x + (2200 x ) ×
90
100
+
15
100
(2200 x ) ×
90
100
                                             =
27
25
x + (2200 x ) ×
90
100
+
27
200
(2200 x )
                                             =
27
25
x + 2200 ×
90
100
x ×
90
100
+
27
200
(2200 x )
                                             =
27
25
x + 1980 x ×
90
100
+
27
200
(2200 x )
                                             =
9
50
x + 1980 +
27
200
(2200 x )
                                             =
9
50
x + 1980 +
27
200
× 2200
27
200
x
                                             =
9
50
x + 1980 + 297
27
200
x
                                             =
9
200
x + 2277
    The equation is transformed into :
     
9
200
x + 2277 = 2200 + 131
     Right side of the equation = 2331
    The equation is transformed into :
     
9
200
x + 2277 = 2331

    Transposition :
     
9
200
x = 23312277

    Combine the items on the right of the equation:
     
9
200
x = 54

    The coefficient of the unknown number is reduced to 1 :
      x = 54 ÷
9
200
        = 54 ×
200
9
        = 6 × 200

    We obtained :
      x = 1200
    This is the solution of the equation.



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