Mathematics
         
语言:中文    Language:English
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (3/2)*((2/3)*(x-4)-6) = 2*x+1 .
    Question type: Equation
    Solution:Original question:
     (3 ÷ 2)((2 ÷ 3)( x 4)6) = 2 x + 1
    Remove the bracket on the left of the equation:
     Left side of the equation = 3 ÷ 2 × ((2 ÷ 3)( x 4)6)
                                             =
3
2
((2 ÷ 3)( x 4)6)
                                             =
3
2
(2 ÷ 3)( x 4)
3
2
× 6
                                             =
3
2
(2 ÷ 3)( x 4)9
                                             =
3
2
× 2 ÷ 3 × ( x 4)9
                                             = 1( x 4)9
                                             = 1 x 1 × 49
                                             = 1 x 49
                                             = 1 x 13
    The equation is transformed into :
     1 x 13 = 2 x + 1

    Transposition :
     1 x 2 x = 1 + 13
    i.e.
      - x = 1 + 13

    Combine the items on the left of the equation:
      - x = 1 + 13

    Combine the items on the right of the equation:
      - x = 14

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
      - 14 = x

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
      x = - 14
    This is the solution of the equation.
    This is the solution of the equation.



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。