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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 80x÷(64*0.08x+32*(1/31*x)/0.21+80x) = 0.05 .
    Question type: Equation
    Solution:Original question:
     80 x ÷ (64 ×
2
25
x + 32(1 ÷ 31 × x ) ÷
21
100
+ 80 x ) =
1
20
     Multiply both sides of the equation by:(64 ×
2
25
x + 32(1 ÷ 31 × x ) ÷
21
100
+ 80 x )
     80 x =
1
20
(64 ×
2
25
x + 32(1 ÷ 31 × x ) ÷
21
100
+ 80 x )
    Remove a bracket on the right of the equation::
     80 x =
1
20
× 64 ×
2
25
x +
1
20
× 32(1 ÷ 31 × x ) ÷
21
100
+
1
20
× 80 x
    The equation is reduced to :
     80 x =
32
125
x +
160
21
(1 ÷ 31 × x ) + 4 x
    The equation is reduced to :
     80 x =
532
125
x +
160
21
(1 ÷ 31 × x )
    Remove a bracket on the right of the equation::
     80 x =
532
125
x +
160
21
× 1 ÷ 31 × x
    The equation is reduced to :
     80 x =
532
125
x +
160
651
x
    The equation is reduced to :
     80 x =
366332
81375
x

    Transposition :
     80 x
366332
81375
x = 0

    Combine the items on the left of the equation:
     
6143668
81375
x = 0

    The coefficient of the unknown number is reduced to 1 :
      x = 0 ÷
6143668
81375
        = 0 ×
81375
6143668

    We obtained :
      x = 0
    However,when simplifying the equation, multiply both sides by (64 ×
2
25
x + 32(1 ÷ 31 × x ) ÷
21
100
+ 80 x ), and when
      x = 0
    , its value is 0. Therefore, the value of this unknown number is not the solution of the equation, and the input to the equation is incorrect.



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