Mathematics
         
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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (1÷10+1÷15)×2+(1÷12+1÷15)x = 1 .
    Question type: Equation
    Solution:Original question:
     (1 ÷ 10 + 1 ÷ 15) × 2 + (1 ÷ 12 + 1 ÷ 15) x = 1
    Remove the bracket on the left of the equation:
     Left side of the equation = 1 ÷ 10 × 2 + 1 ÷ 15 × 2 + (1 ÷ 12 + 1 ÷ 15) x
                                             =
1
5
+
2
15
+ (1 ÷ 12 + 1 ÷ 15) x
                                             =
1
3
+ (1 ÷ 12 + 1 ÷ 15) x
                                             =
1
3
+ 1 ÷ 12 × x + 1 ÷ 15 × x
                                             =
1
3
+
1
12
x +
1
15
x
                                             =
1
3
+
3
20
x
    The equation is transformed into :
     
1
3
+
3
20
x = 1

    Transposition :
     
3
20
x = 1
1
3

    Combine the items on the right of the equation:
     
3
20
x =
2
3

    The coefficient of the unknown number is reduced to 1 :
      x =
2
3
÷
3
20
        =
2
3
×
20
3

    We obtained :
      x =
40
9
    This is the solution of the equation.

    Convert the result to decimal form :
      x = 4.444444



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