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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (58.55-x)/(1/2183.5)+0.00009 = (x-30)/(1/1182.17)+0.00018 .
    Question type: Equation
    Solution:Original question:
     (
1171
20
 − x ) ÷ (1 ÷
4367
2
) +
9
100000
 = ( x − 30) ÷ (1 ÷
118217
100
) +
9
50000
     Multiply both sides of the equation by:(1 ÷
4367
2
) ,  (1 ÷
118217
100
)
     (
1171
20
 − x )(1 ÷
118217
100
) +
9
100000
(1 ÷
4367
2
)(1 ÷
118217
100
) = ( x − 30)(1 ÷
4367
2
) +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    Remove a bracket on the left of the equation:：
     
1171
20
(1 ÷
118217
100
) − x (1 ÷
118217
100
) +
9
100000
(1 ÷
4367
2
)(1 ÷
118217
100
) = ( x − 30)(1 ÷
4367
2
) +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    Remove a bracket on the right of the equation:：
     
1171
20
(1 ÷
118217
100
) − x (1 ÷
118217
100
) +
9
100000
(1 ÷
4367
2
)(1 ÷
118217
100
) = x (1 ÷
4367
2
) − 30(1 ÷
4367
2
) +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    Remove a bracket on the left of the equation:
     
1171
20
 × 1 ÷
118217
100
 − x (1 ÷
118217
100
) +
9
100000
(1 ÷
4367
2
)(1 ÷
118217
100
) = x (1 ÷
4367
2
) − 30(1 ÷
4367
2
) +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    Remove a bracket on the right of the equation:：
     
1171
20
 × 1 ÷
118217
100
 − x (1 ÷
118217
100
) +
9
100000
(1 ÷
4367
2
)(1 ÷
118217
100
) = x × 1 ÷
4367
2
 − 30(1 ÷
4367
2
) +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    The equation is reduced to :
     
5855
118217
 − x (1 ÷
118217
100
) +
9
100000
(1 ÷
4367
2
)(1 ÷
118217
100
) = x ×
2
4367
 − 30(1 ÷
4367
2
) +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    Remove a bracket on the left of the equation:
     
5855
118217
 − x × 1 ÷
118217
100
 +
9
100000
(1 ÷
4367
2
)(1 ÷
118217
100
) =
2
4367
 x − 30(1 ÷
4367
2
) +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    Remove a bracket on the right of the equation:：
     
5855
118217
 − x × 1 ÷
118217
100
 +
9
100000
(1 ÷
4367
2
)(1 ÷
118217
100
) =
2
4367
 x − 30 × 1 ÷
4367
2
 +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    The equation is reduced to :
     
5855
118217
 − x ×
100
118217
 +
9
100000
(1 ÷
4367
2
)(1 ÷
118217
100
) =
2
4367
 x −
60
4367
 +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    Remove a bracket on the left of the equation:
     
5855
118217
 −
100
118217
 x +
9
100000
 × 1 ÷
4367
2
 × (1 ÷
118217
100
) =
2
4367
 x −
60
4367
 +
9
50000
(1 ÷
4367
2
)(1 ÷
118217
100
)
    Remove a bracket on the right of the equation:：
     
5855
118217
 −
100
118217
 x +
9
100000
 × 1 ÷
4367
2
 × (1 ÷
118217
100
) =
2
4367
 x −
60
4367
 +
9
50000
 × 1 ÷
4367
2
 × (1 ÷
118217
100
)
    The equation is reduced to :
     
5855
118217
 −
100
118217
 x +
9
218350000
(1 ÷
118217
100
) =
2
4367
 x −
60
4367
 +
9
109175000
(1 ÷
118217
100
)
    Remove a bracket on the left of the equation:
     
5855
118217
 −
100
118217
 x +
9
218350000
 × 1 ÷
118217
100
 =
2
4367
 x −
60
4367
 +
9
109175000
(1 ÷
118217
100
)
    Remove a bracket on the right of the equation:：
     
5855
118217
 −
100
118217
 x +
9
218350000
 × 1 ÷
118217
100
 =
2
4367
 x −
60
4367
 +
9
109175000
 × 1 ÷
118217
100

    
        x≈58.55 , keep 2 decimal places    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》


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