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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 3.5*120+3.2(x-120) = 3.5*120+3.2(400-x-120) .
    Question type: Equation
    Solution:Original question:
     
7
2
× 120 +
16
5
( x 120) =
7
2
× 120 +
16
5
(400 x 120)
     Left side of the equation = 420 +
16
5
( x 120)
    The equation is transformed into :
     420 +
16
5
( x 120) =
7
2
× 120 +
16
5
(400 x 120)
    Remove the bracket on the left of the equation:
     Left side of the equation = 420 +
16
5
x
16
5
× 120
                                             = 420 +
16
5
x 384
                                             = 36 +
16
5
x
    The equation is transformed into :
     36 +
16
5
x =
7
2
× 120 +
16
5
(400 x 120)
     Right side of the equation = 420 +
16
5
(400 x 120)
    The equation is transformed into :
     36 +
16
5
x = 420 +
16
5
(400 x 120)
    Remove the bracket on the right of the equation:
     Right side of the equation = 420 +
16
5
× 400
16
5
x
16
5
× 120
                                               = 420 + 1280
16
5
x 384
                                               = 1316
16
5
x
    The equation is transformed into :
     36 +
16
5
x = 1316
16
5
x

    Transposition :
     
16
5
x +
16
5
x = 131636

    Combine the items on the left of the equation:
     
32
5
x = 131636

    Combine the items on the right of the equation:
     
32
5
x = 1280

    The coefficient of the unknown number is reduced to 1 :
      x = 1280 ÷
32
5
        = 1280 ×
5
32
        = 40 × 5

    We obtained :
      x = 200
    This is the solution of the equation.



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