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On line Solution of Monovariate Equation：
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation 3080x2-{[3080/(1+12%)]+[3080/(1-12%)]} = 0 .
Question type: Equation
Solution:Original question:
| 3080 | x | × | 2 | − | ( | ( | 3080 | ÷ | ( | 1 | + | 12 100 | ) | ) | + | ( | 3080 | ÷ | ( | 1 | − | 12 100 | ) | ) | ) | = | 0 |
| 3080 | x | × | 2 | − | ( | 3080 | ÷ | ( | 1 | + | 12 100 | ) | ) | − | ( | 3080 | ÷ | ( | 1 | − | 12 100 | ) | ) | = | 0 |
| 6160 | x | − | ( | 3080 | ÷ | ( | 1 | + | 12 100 | ) | ) | − | ( | 3080 | ÷ | ( | 1 | − | 12 100 | ) | ) | = | 0 |
| 6160 | x | − | 3080 | ÷ | ( | 1 | + | 12 100 | ) | − | ( | 3080 | ÷ | ( | 1 | − | 12 100 | ) | ) | = | 0 |
| Multiply both sides of the equation by: | ( | 1 | + | 12 100 | ) |
| 6160 | x | ( | 1 | + | 12 100 | ) | − | 3080 | − | ( | 3080 | ÷ | ( | 1 | − | 12 100 | ) | ) | ( | 1 | + | 12 100 | ) | = | 0 |
| 6160 | x | × | 1 | + | 6160 | x | × | 12 100 | − | 3080 | − | ( | 3080 | ÷ | ( | 1 | − | 12 100 | ) | ) | ( | 1 | + | 12 100 | ) | = | 0 |
| 6160 | x | + | 3696 5 | x | − | 3080 | − | ( | 3080 | ÷ | ( | 1 | − | 12 100 | ) | ) | ( | 1 | + | 12 100 | ) | = | 0 |
34496 5 | x | − | 3080 | − | ( | 3080 | ÷ | ( | 1 | − | 12 100 | ) | ) | ( | 1 | + | 12 100 | ) | = | 0 |
34496 5 | x | − | 3080 | − | 3080 | ÷ | ( | 1 | − | 12 100 | ) | × | ( | 1 | + | 12 100 | ) | = | 0 |
| Multiply both sides of the equation by: | ( | 1 | − | 12 100 | ) |
34496 5 | x | ( | 1 | − | 12 100 | ) | − | 3080 | ( | 1 | − | 12 100 | ) | − | 3080 | ( | 1 | + | 12 100 | ) | = | 0 |
34496 5 | x | × | 1 | − | 34496 5 | x | × | 12 100 | − | 3080 | ( | 1 | − | 12 100 | ) | − | 3080 | ( | 1 | + | 12 100 | ) | = | 0 |
34496 5 | x | − | 103488 125 | x | − | 3080 | ( | 1 | − | 12 100 | ) | − | 3080 | ( | 1 | + | 12 100 | ) | = | 0 |
758912 125 | x | − | 3080 | ( | 1 | − | 12 100 | ) | − | 3080 | ( | 1 | + | 12 100 | ) | = | 0 |
758912 125 | x | − | 3080 | × | 1 | + | 3080 | × | 12 100 | − | 3080 | ( | 1 | + | 12 100 | ) | = | 0 |
758912 125 | x | − | 3080 | + | 1848 5 | − | 3080 | ( | 1 | + | 12 100 | ) | = | 0 |
758912 125 | x | − | 13552 5 | − | 3080 | ( | 1 | + | 12 100 | ) | = | 0 |
758912 125 | x | − | 13552 5 | − | 3080 | × | 1 | − | 3080 | × | 12 100 | = | 0 |
758912 125 | x | − | 13552 5 | − | 3080 | − | 1848 5 | = | 0 |
758912 125 | x | − | 6160 | = | 0 |
Transposition :
758912 125 | x | = | 0 | + | 6160 |
Combine the items on the right of the equation:
758912 125 | x | = | 6160 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 6160 | ÷ | 758912 125 |
| = | 6160 | × | 125 758912 |
| = | 5 | × | 125 616 |
We obtained :
| x | = | 625 616 |
Convert the result to decimal form :
| x | = | 1.01461 |