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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 16.1*200*x*(1322-x/2)+16.1*(653.3-200)*120*(1322-60) = 3202.87 .
    Question type: Equation
    Solution:Original question:
     
161
10
× 200 x (1322 x ÷ 2) +
161
10
(
6533
10
200) × 120(132260) =
320287
100
     Left side of the equation = 3220 x (1322 x ÷ 2) + 1932(
6533
10
200)(132260)
    The equation is transformed into :
     3220 x (1322 x ÷ 2) + 1932(
6533
10
200)(132260) =
320287
100
    Remove the bracket on the left of the equation:
     Left side of the equation = 3220 x × 13223220 x x ÷ 2 + 1932(
6533
10
200)(132260)
                                             = 4256840 x 1610 x x + 1932(
6533
10
200)(132260)
                                             = 4256840 x 1610 x x + 1932 ×
6533
10
(132260)1932 × 200(132260)
                                             = 4256840 x 1610 x x +
6310878
5
(132260)386400(132260)
                                             = 4256840 x 1610 x x +
6310878
5
× 1322
6310878
5
× 60386400(132260)
                                             = 4256840 x 1610 x x +
8342980716
5
75730536386400(132260)
                                             = 4256840 x 1610 x x +
7964328036
5
386400(132260)
                                             = 4256840 x 1610 x x +
7964328036
5
386400 × 1322 + 386400 × 60
                                             = 4256840 x 1610 x x +
7964328036
5
510820800 + 23184000
                                             = 4256840 x 1610 x x +
5526144036
5
    The equation is transformed into :
     4256840 x 1610 x x +
5526144036
5
=
320287
100

    
        x≈-238.179326 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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