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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 49+0.2*(t-200)+0.3*40 = 69+0.15*(t-250) .
    Question type: Equation
    Solution:Original question:
     49 +
1
5
( t 200) +
3
10
× 40 = 69 +
3
20
( t 250)
     Left side of the equation = 49 +
1
5
( t 200) + 12
                                             = 61 +
1
5
( t 200)
    The equation is transformed into :
     61 +
1
5
( t 200) = 69 +
3
20
( t 250)
    Remove the bracket on the left of the equation:
     Left side of the equation = 61 +
1
5
t
1
5
× 200
                                             = 61 +
1
5
t 40
                                             = 21 +
1
5
t
    The equation is transformed into :
     21 +
1
5
t = 69 +
3
20
( t 250)
    Remove the bracket on the right of the equation:
     Right side of the equation = 69 +
3
20
t
3
20
× 250
                                               = 69 +
3
20
t
75
2
                                               =
63
2
+
3
20
t
    The equation is transformed into :
     21 +
1
5
t =
63
2
+
3
20
t

    Transposition :
     
1
5
t
3
20
t =
63
2
21

    Combine the items on the left of the equation:
     
1
20
t =
63
2
21

    Combine the items on the right of the equation:
     
1
20
t =
21
2

    The coefficient of the unknown number is reduced to 1 :
      t =
21
2
÷
1
20
        =
21
2
× 20
        = 21 × 10

    We obtained :
      t = 210
    This is the solution of the equation.



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