Mathematics
         
语言：中文    Language:English
Equations   
Fold
Unary equation
Multivariate equation
Math OP  
Unfold
Linear algebra      
Unfold
Derivative function
Function image
Hot issues
On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1017×[（1+0.0435）1-1]+（80+32.91+0.01V）×[（1+0.0435）0.5-1] = 0 .
    Question type: Equation
    Solution:Original question:
     1017((1 +
87
2000
) × 1 − 1) + (80 +
3291
100
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = 1017(1 +
87
2000
) × 1 − 1017 × 1 + (80 +
3291
100
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             = 1017(1 +
87
2000
) − 1017 + (80 +
3291
100
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             = 1017 × 1 + 1017 ×
87
2000
 − 1017 + (80 +
3291
100
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             = 1017 +
88479
2000
 − 1017 + (80 +
3291
100
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             =
88479
2000
 + (80 +
3291
100
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             =
88479
2000
 + 80((1 +
87
2000
) ×
1
2
 − 1) +
3291
100
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             =
88479
2000
 + 80(1 +
87
2000
) ×
1
2
 − 80 × 1 +
3291
100
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             =
88479
2000
 + 40(1 +
87
2000
) − 80 +
3291
100
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
71521
2000
 + 40(1 +
87
2000
) +
3291
100
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
71521
2000
 + 40 × 1 + 40 ×
87
2000
 +
3291
100
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
71521
2000
 + 40 +
87
50
 +
3291
100
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             =
11959
2000
 +
3291
100
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             =
11959
2000
 +
3291
100
(1 +
87
2000
) ×
1
2
 −
3291
100
 × 1 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             =
11959
2000
 +
3291
200
(1 +
87
2000
) −
3291
100
 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
53861
2000
 +
3291
200
(1 +
87
2000
) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
53861
2000
 +
3291
200
 × 1 +
3291
200
 ×
87
2000
 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
53861
2000
 +
3291
200
 +
286317
400000
 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
3903883
400000
 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
3903883
400000
 +
1
100
 V (1 +
87
2000
) ×
1
2
 −
1
100
 V × 1
                                             = -
3903883
400000
 +
1
200
 V (1 +
87
2000
) −
1
100
 V
                                             = -
3903883
400000
 +
1
200
 V × 1 +
1
200
 V ×
87
2000
 −
1
100
 V
                                             = -
3903883
400000
 +
1
200
 V +
87
400000
 V −
1
100
 V
                                             = -
3903883
400000
 −
1913
400000
 V
    The equation is transformed into :
      -
3903883
400000
 −
1913
400000
 V = 0

    Transposition :
      -
1913
400000
 V = 0 +
3903883
400000

    Combine the items on the right of the equation:
      -
1913
400000
 V =
3903883
400000

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
      -
3903883
400000
 =
1913
400000
 V

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
1913
400000
 V = -
3903883
400000

    The coefficient of the unknown number is reduced to 1 :
      V = -
3903883
400000
 ÷
1913
400000
        = -
3903883
400000
 ×
400000
1913
        = - 3903883 ×
1
1913

    We obtained :
      V = -
3903883
1913
    This is the solution of the equation.

    Convert the result to decimal form :
      V = - 2040.712493



Your problem has not been solved here? Please go to the Hot Problems section！


Return



  New addition:Lenders ToolBox module（Specific location：Math OP > Lenders ToolBox ），welcome。