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On line Solution of Monovariate Equation：
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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 30×[（1+0.0435）1-1]+（600+80+220+21.5+19.03+0.01K8)[(1+0.0435)0.5-1] = 0 .
    Question type: Equation
    Solution:Original question:
     30((1 +
87
2000
) × 1 − 1) + (600 + 80 + 220 +
43
2
 +
1903
100
 +
1
100
 K × 8)((1 +
87
2000
) ×
1
2
 − 1) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = 30(1 +
87
2000
) × 1 − 30 × 1 + (600 + 80 + 220 +
43
2
 +
1903
100
 +
1
100
 K × 8)((1 +
87
2000
) ×
1
2
 − 1)
                                             = 30(1 +
87
2000
) − 30 + (600 + 80 + 220 +
43
2
 +
1903
100
 +
1
100
 K × 8)((1 +
87
2000
) ×
1
2
 − 1)
                                             = 30 × 1 + 30 ×
87
2000
 − 30 + (600 + 80 + 220 +
43
2
 +
1903
100
 +
1
100
 K × 8)((1 +
87
2000
) ×
1
2
 − 1)
                                             = 30 +
261
200
 − 30 + (600 + 80 + 220 +
43
2
 +
1903
100
 +
1
100
 K × 8)((1 +
87
2000
) ×
1
2
 − 1)
                                             =
261
200
 + (600 + 80 + 220 +
43
2
 +
1903
100
 +
1
100
 K × 8)((1 +
87
2000
) ×
1
2
 − 1)
                                             =
261
200
 + 600((1 +
87
2000
) ×
1
2
 − 1) + 80((1 +
87
2000
) ×
1
2
 − 1) + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
                                             =
261
200
 + 600((1 +
87
2000
) ×
1
2
 − 1) + 80((1 +
87
2000
) ×
1
2
 − 1) + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
                                             =
261
200
 + 600(1 +
87
2000
) ×
1
2
 − 600 × 1 + 80((1 +
87
2000
) ×
1
2
 − 1) + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1)
                                             =
261
200
 + 300(1 +
87
2000
) − 600 + 80((1 +
87
2000
) ×
1
2
 − 1) + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
119739
200
 + 300(1 +
87
2000
) + 80((1 +
87
2000
) ×
1
2
 − 1) + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
                                             = -
119739
200
 + 300 × 1 + 300 ×
87
2000
 + 80((1 +
87
2000
) ×
1
2
 − 1) + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
                                             = -
119739
200
 + 300 +
261
20
 + 80((1 +
87
2000
) ×
1
2
 − 1) + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
                                             = -
57129
200
 + 80((1 +
87
2000
) ×
1
2
 − 1) + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
57129
200
 + 80(1 +
87
2000
) ×
1
2
 − 80 × 1 + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
57129
200
 + 40(1 +
87
2000
) − 80 + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K
                                             = -
73129
200
 + 40(1 +
87
2000
) + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
73129
200
 + 40 × 1 + 40 ×
87
2000
 + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
                                             = -
73129
200
 + 40 +
87
50
 + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
64781
200
 + 220((1 +
87
2000
) ×
1
2
 − 1) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
64781
200
 + 220(1 +
87
2000
) ×
1
2
 − 220 × 1 +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K
                                             = -
64781
200
 + 110(1 +
87
2000
) − 220 +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
108781
200
 + 110(1 +
87
2000
) +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
108781
200
 + 110 × 1 + 110 ×
87
2000
 +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
108781
200
 + 110 +
957
200
 +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
10728
25
 +
43
2
((1 +
87
2000
) ×
1
2
 − 1) +
1903
100
((1 +
87
2000
) ×
1
2
 − 1) +
2
25
 K ((1 +
87
2000
) ×
1
2
 − 1)

    
        K≈-11722.516270 , keep 6 decimal places    
    There are 1 solution(s).

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