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    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation [X×365×1+300-(1500+0.15×365×X)/0.4529]×(1-25%)+611.83 = 661.5 .
    Question type: Equation
    Solution:Original question:
     ( X × 365 × 1 + 300(1500 +
3
20
× 365 X ) ÷
4529
10000
)(1
25
100
) +
61183
100
=
1323
2
    Remove the bracket on the left of the equation:
     Left side of the equation = X × 365 × 1(1
25
100
) + 300(1
25
100
)(1500 +
3
20
× 365 X ) ÷
4529
10000
× (1
25
100
) +
61183
100
                                             = X × 365(1
25
100
) + 300(1
25
100
)(1500 +
3
20
× 365 X ) ×
10000
4529
(1
25
100
) +
61183
100
                                             = X × 365 × 1 X × 365 ×
25
100
+ 300(1
25
100
)(1500 +
3
20
× 365 X ) ×
10000
4529
(1
25
100
) +
61183
100
                                             = X × 365 X ×
365
4
+ 300(1
25
100
)(1500 +
3
20
× 365 X ) ×
10000
4529
(1
25
100
) +
61183
100
                                             =
1095
4
X + 300(1
25
100
)(1500 +
3
20
× 365 X ) ×
10000
4529
(1
25
100
) +
61183
100
                                             =
1095
4
X + 300 × 1300 ×
25
100
(1500 +
3
20
× 365 X ) ×
10000
4529
(1
25
100
) +
61183
100
                                             =
1095
4
X + 30075(1500 +
3
20
× 365 X ) ×
10000
4529
(1
25
100
) +
61183
100
                                             =
1095
4
X +
83683
100
(1500 +
3
20
× 365 X ) ×
10000
4529
(1
25
100
)
                                             =
1095
4
X +
83683
100
1500 ×
10000
4529
(1
25
100
)
3
20
× 365 X ×
10000
4529
(1
25
100
)
                                             =
1095
4
X +
83683
100
15000000
4529
(1
25
100
)
547500
4529
X (1
25
100
)
                                             =
1095
4
X +
83683
100
15000000
4529
× 1 +
15000000
4529
×
25
100
547500
4529
X (1
25
100
)
                                             =
1095
4
X +
83683
100
15000000
4529
+
3750000
4529
547500
4529
X (1
25
100
)

    
        X≈12.609832 , keep 6 decimal places
    
    There are 1 solution(s).


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