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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (4-0.8)/(4-0.12)*(39331-X)*0.15/2+0.2X = 3983.63 .
    Question type: Equation
    Solution:Original question:
     (4
4
5
) ÷ (4
3
25
) × (39331 X ) ×
3
20
÷ 2 +
1
5
X =
398363
100
     Multiply both sides of the equation by:(4
3
25
)
     (4
4
5
)(39331 X ) ×
3
20
÷ 2 +
1
5
X (4
3
25
) =
398363
100
(4
3
25
)
    Remove a bracket on the left of the equation::
     4(39331 X ) ×
3
20
÷ 2
4
5
(39331 X ) ×
3
20
÷ 2 +
1
5
X (4
3
25
) =
398363
100
(4
3
25
)
    Remove a bracket on the right of the equation::
     4(39331 X ) ×
3
20
÷ 2
4
5
(39331 X ) ×
3
20
÷ 2 +
1
5
X (4
3
25
) =
398363
100
× 4
398363
100
×
3
25
    The equation is reduced to :
     
3
10
(39331 X )
3
50
(39331 X ) +
1
5
X (4
3
25
) =
398363
25
1195089
2500
    The equation is reduced to :
     
3
10
(39331 X )
3
50
(39331 X ) +
1
5
X (4
3
25
) =
38641211
2500
    Remove a bracket on the left of the equation:
     
3
10
× 39331
3
10
X
3
50
(39331 X ) +
1
5
X (4
3
25
) =
38641211
2500
    The equation is reduced to :
     
117993
10
3
10
X
3
50
(39331 X ) +
1
5
X (4
3
25
) =
38641211
2500
    Remove a bracket on the left of the equation:
     
117993
10
3
10
X
3
50
× 39331 +
3
50
X +
1
5
X (4
3
25
) =
38641211
2500
    The equation is reduced to :
     
117993
10
3
10
X
117993
50
+
3
50
X +
1
5
X (4
3
25
) =
38641211
2500
    The equation is reduced to :
     
235986
25
6
25
X +
1
5
X (4
3
25
) =
38641211
2500
    Remove a bracket on the left of the equation:
     
235986
25
6
25
X +
1
5
X × 4
1
5
X ×
3
25
=
38641211
2500
    The equation is reduced to :
     
235986
25
6
25
X +
4
5
X
3
125
X =
38641211
2500
    The equation is reduced to :
     
235986
25
+
67
125
X =
38641211
2500

    Transposition :
     
67
125
X =
38641211
2500
235986
25

    Combine the items on the right of the equation:
     
67
125
X =
15042611
2500

    The coefficient of the unknown number is reduced to 1 :
      X =
15042611
2500
÷
67
125
        =
15042611
2500
×
125
67
        =
15042611
20
×
1
67

    We obtained :
      X =
15042611
1340
    This is the solution of the equation.

    Convert the result to decimal form :
      X = 11225.829104



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