Mathematics
         
语言:中文    Language:English
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation [2/(x+1)]-1 = 1/(1-x) .
    Question type: Equation
    Solution:Original question:
     (2 ÷ ( x + 1))1 = 1 ÷ (1 x )
     Multiply both sides of the equation by:(1 x )
     (2 ÷ ( x + 1))(1 x )1(1 x ) = 1
    Remove a bracket on the left of the equation::
     2 ÷ ( x + 1) × (1 x )1(1 x ) = 1
     Multiply both sides of the equation by:( x + 1)
     2(1 x )1(1 x )( x + 1) = 1( x + 1)
    Remove a bracket on the left of the equation:
     2 × 12 x 1(1 x )( x + 1) = 1( x + 1)
    Remove a bracket on the right of the equation::
     2 × 12 x 1(1 x )( x + 1) = 1 x + 1 × 1
    The equation is reduced to :
     22 x 1(1 x )( x + 1) = 1 x + 1
    Remove a bracket on the left of the equation:
     22 x 1 × 1( x + 1) + 1 x ( x + 1) = 1 x + 1
    The equation is reduced to :
     22 x 1( x + 1) + 1 x ( x + 1) = 1 x + 1
    Remove a bracket on the left of the equation:
     22 x 1 x 1 × 1 + 1 x ( x + 1) = 1 x + 1
    The equation is reduced to :
     22 x 1 x 1 + 1 x ( x + 1) = 1 x + 1
    The equation is reduced to :
     13 x + 1 x ( x + 1) = 1 x + 1
    Remove a bracket on the left of the equation:
     13 x + 1 x x + 1 x × 1 = 1 x + 1
    The equation is reduced to :
     13 x + 1 x x + 1 x = 1 x + 1
    The equation is reduced to :
     12 x + 1 x x = 1 x + 1

    After the equation is converted into a general formula, it is converted into:
    ( x - 0 )( x - 3 )=0
    From
        x - 0 = 0
        x - 3 = 0

    it is concluded that::
        x1=0
        x2=3
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。