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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (2142.45-2086)➗(2114-2086) = (1984.7-1933.77)➗(x-1933.77) .
    Question type: Equation
    Solution:Original question:
     (
42849
20
2086) ÷ (21142086) = (
19847
10
193377
100
) ÷ ( x
193377
100
)
     Multiply both sides of the equation by:(21142086) ,  ( x
193377
100
)
     (
42849
20
2086)( x
193377
100
) = (
19847
10
193377
100
)(21142086)
    Remove a bracket on the left of the equation::
     
42849
20
( x
193377
100
)2086( x
193377
100
) = (
19847
10
193377
100
)(21142086)
    Remove a bracket on the right of the equation::
     
42849
20
( x
193377
100
)2086( x
193377
100
) =
19847
10
(21142086)
193377
100
(21142086)
    Remove a bracket on the left of the equation:
     
42849
20
x
42849
20
×
193377
100
2086( x
193377
100
) =
19847
10
(21142086)
193377
100
(21142086)
    Remove a bracket on the right of the equation::
     
42849
20
x
42849
20
×
193377
100
2086( x
193377
100
) =
19847
10
× 2114
19847
10
× 2086
193377
100
(21142086)
    The equation is reduced to :
     
42849
20
x
8286011073
2000
2086( x
193377
100
) =
20978279
5
20700421
5
193377
100
(21142086)
    The equation is reduced to :
     
42849
20
x
8286011073
2000
2086( x
193377
100
) =
277858
5
193377
100
(21142086)
    Remove a bracket on the left of the equation:
     
42849
20
x
8286011073
2000
2086 x + 2086 ×
193377
100
=
277858
5
193377
100
(21142086)
    Remove a bracket on the right of the equation::
     
42849
20
x
8286011073
2000
2086 x + 2086 ×
193377
100
=
277858
5
193377
100
× 2114 +
193377
100
× 2086
    The equation is reduced to :
     
42849
20
x
8286011073
2000
2086 x +
201692211
50
=
277858
5
204399489
50
+
201692211
50

    
        x≈1959.032002 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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