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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation z = 1.032-6.34*0.032*(z-0.032)/z/(z*0.032) .
    Question type: Equation
    Solution:Original question:
      z =
129
125
 −
317
50
 ×
4
125
( z −
4
125
) ÷ z ÷ ( z ×
4
125
)
     Multiply both sides of the equation by: z
      z z =
129
125
 z −
317
50
 ×
4
125
( z −
4
125
) ÷ ( z ×
4
125
)
    Remove a bracket on the right of the equation:：
      z z =
129
125
 z −
317
50
 ×
4
125
 z ÷ ( z ×
4
125
) +
317
50
 ×
4
125
 ×
4
125
 ÷ ( z ×
4
125
)
    The equation is reduced to :
      z z =
129
125
 z −
634
3125
 z ÷ ( z ×
4
125
) +
2536
390625
 ÷ ( z ×
4
125
)
     Multiply both sides of the equation by:(1 ×
4
125
)
      z z (1 ×
4
125
) =
129
125
 z (1 ×
4
125
) −
634
3125
 × 1 +
2536
390625
 ÷ ( z ×
4
125
) × (1 ×
4
125
)
    Remove a bracket on the left of the equation:
      z z × 1 ×
4
125
 =
129
125
 z (1 ×
4
125
) −
634
3125
 × 1 +
2536
390625
 ÷ ( z ×
4
125
) × (1 ×
4
125
)
    Remove a bracket on the right of the equation:：
      z z × 1 ×
4
125
 =
129
125
 z × 1 ×
4
125
 −
634
3125
 × 1 +
2536
390625
 ÷ ( z ×
4
125
) × (1 ×
4
125
)
    The equation is reduced to :
      z z ×
4
125
 =
516
15625
 z −
634
3125
 +
2536
390625
 ÷ ( z ×
4
125
) × (1 ×
4
125
)
     Multiply both sides of the equation by:( z ×
4
125
)
      z z ×
4
125
( z ×
4
125
) =
516
15625
 z ( z ×
4
125
) −
634
3125
( z ×
4
125
) +
2536
390625
(1 ×
4
125
)
    Remove a bracket on the left of the equation:
      z z ×
4
125
 z ×
4
125
 =
516
15625
 z ( z ×
4
125
) −
634
3125
( z ×
4
125
) +
2536
390625
(1 ×
4
125
)
    Remove a bracket on the right of the equation:：
      z z ×
4
125
 z ×
4
125
 =
516
15625
 z z ×
4
125
 −
634
3125
( z ×
4
125
) +
2536
390625
(1 ×
4
125
)
    The equation is reduced to :
      z z ×
16
15625
 z =
2064
1953125
 z z −
634
3125
( z ×
4
125
) +
2536
390625
(1 ×
4
125
)
    Remove a bracket on the right of the equation:：
      z z ×
16
15625
 z =
2064
1953125
 z z −
634
3125
 z ×
4
125
 +
2536
390625
(1 ×
4
125
)
    The equation is reduced to :
      z z ×
16
15625
 z =
2064
1953125
 z z −
2536
390625
 z +
2536
390625
(1 ×
4
125
)
    Remove a bracket on the right of the equation:：
      z z ×
16
15625
 z =
2064
1953125
 z z −
2536
390625
 z +
2536
390625
 × 1 ×
4
125
    The equation is reduced to :
      z z ×
16
15625
 z =
2064
1953125
 z z −
2536
390625
 z +
10144
48828125

    the solutions is:
        z≈0.032163 , keep 6 decimal places    
    There are 1 solution(s).

解方程的详细方法请参阅：《方程的解法》


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