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On line Solution of Monovariate Equation：
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
Overview: 1 questions will be solved this time.Among them
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[ 1/1 Equation]
Work: Find the solution of equation (12-3)(2+X)(3-2) = 128-(30-(7+(5-2))) .
Question type: Equation
Solution:Original question:
| ( | 12 | − | 3 | ) | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) | = | 128 | − | ( | 30 | − | ( | 7 | + | ( | 5 | − | 2 | ) | ) | ) |
| Left side of the equation = | 12 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) | − | 3 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) |
| = | 12 | × | 2 | ( | 3 | − | 2 | ) | + | 12 | X | ( | 3 | − | 2 | ) | − | 3 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) |
| = | 24 | ( | 3 | − | 2 | ) | + | 12 | X | ( | 3 | − | 2 | ) | − | 3 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) |
| = | 24 | × | 3 | − | 24 | × | 2 | + | 12 | X | ( | 3 | − | 2 | ) | − | 3 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) |
| = | 72 | − | 48 | + | 12 | X | ( | 3 | − | 2 | ) | − | 3 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) |
| = | 24 | + | 12 | X | ( | 3 | − | 2 | ) | − | 3 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) |
| = | 24 | + | 12 | X | × | 3 | − | 12 | X | × | 2 | − | 3 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) |
| = | 24 | + | 36 | X | − | 24 | X | − | 3 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) |
| = | 24 | + | 12 | X | − | 3 | ( | 2 | + | X | ) | ( | 3 | − | 2 | ) |
| = | 24 | + | 12 | X | − | 3 | × | 2 | ( | 3 | − | 2 | ) | − | 3 | X | ( | 3 | − | 2 | ) |
| = | 24 | + | 12 | X | − | 6 | ( | 3 | − | 2 | ) | − | 3 | X | ( | 3 | − | 2 | ) |
| = | 24 | + | 12 | X | − | 6 | × | 3 | + | 6 | × | 2 | − | 3 | X | ( | 3 | − | 2 | ) |
| = | 24 | + | 12 | X | − | 18 | + | 12 | − | 3 | X | ( | 3 | − | 2 | ) |
| = | 18 | + | 12 | X | − | 3 | X | ( | 3 | − | 2 | ) |
| = | 18 | + | 12 | X | − | 3 | X | × | 3 | + | 3 | X | × | 2 |
| = | 18 | + | 12 | X | − | 9 | X | + | 6 | X |
| = | 18 | + | 9 | X |
| 18 | + | 9 | X | = | 128 | − | ( | 30 | − | ( | 7 | + | ( | 5 | − | 2 | ) | ) | ) |
| Right side of the equation = | 128 | − | 30 | + | ( | 7 | + | ( | 5 | − | 2 | ) | ) |
| = | 98 | + | ( | 7 | + | ( | 5 | − | 2 | ) | ) |
| = | 98 | + | 7 | + | ( | 5 | − | 2 | ) |
| = | 105 | + | ( | 5 | − | 2 | ) |
| = | 105 | + | 5 | − | 2 |
| = | 108 |
| 18 | + | 9 | X | = | 108 |
| 18 | + | 9 | X | = | 108 |
Transposition :
| 9 | X | = | 108 | − | 18 |
Combine the items on the right of the equation:
| 9 | X | = | 90 |
The coefficient of the unknown number is reduced to 1 :
| X | = | 90 | ÷ | 9 |
| = | 90 | × | 1 9 |
| = | 10 | × | 1 |
We obtained :
| X | = | 10 |