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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 20((X+1+5/4)/(2/(2/5)))/(2/3) = (2+3)(3)/(1/3) .
    Question type: Equation
    Solution:Original question:
     20(( X + 1 + 5 ÷ 4) ÷ (2 ÷ (2 ÷ 5))) ÷ (2 ÷ 3) = (2 + 3)(3) ÷ (1 ÷ 3)
     Multiply both sides of the equation by:(2 ÷ 3) ,  (1 ÷ 3)
     20(( X + 1 + 5 ÷ 4) ÷ (2 ÷ (2 ÷ 5)))(1 ÷ 3) = (2 + 3)(3)(2 ÷ 3)
    Remove a bracket on the left of the equation::
     20( X + 1 + 5 ÷ 4) ÷ (2 ÷ (2 ÷ 5)) × (1 ÷ 3) = (2 + 3)(3)(2 ÷ 3)
    Remove a bracket on the right of the equation::
     20( X + 1 + 5 ÷ 4) ÷ (2 ÷ (2 ÷ 5)) × (1 ÷ 3) = 2(3)(2 ÷ 3) + 3(3)(2 ÷ 3)
     Multiply both sides of the equation by:(2 ÷ (2 ÷ 5))
     20( X + 1 + 5 ÷ 4)(1 ÷ 3) = 2(3)(2 ÷ 3)(2 ÷ (2 ÷ 5)) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
    Remove a bracket on the left of the equation:
     20 X (1 ÷ 3) + 20 × 1(1 ÷ 3) + 20 × 5 ÷ 4 × (1 ÷ 3) = 2(3)(2 ÷ 3)(2 ÷ (2 ÷ 5)) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
    Remove a bracket on the right of the equation::
     20 X (1 ÷ 3) + 20 × 1(1 ÷ 3) + 20 × 5 ÷ 4 × (1 ÷ 3) = 2 × 3(2 ÷ 3)(2 ÷ (2 ÷ 5)) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
    The equation is reduced to :
     20 X (1 ÷ 3) + 20(1 ÷ 3) + 25(1 ÷ 3) = 6(2 ÷ 3)(2 ÷ (2 ÷ 5)) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
    Remove a bracket on the left of the equation:
     20 X × 1 ÷ 3 + 20(1 ÷ 3) + 25(1 ÷ 3) = 6(2 ÷ 3)(2 ÷ (2 ÷ 5)) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
    Remove a bracket on the right of the equation::
     20 X × 1 ÷ 3 + 20(1 ÷ 3) + 25(1 ÷ 3) = 6 × 2 ÷ 3 × (2 ÷ (2 ÷ 5)) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
    The equation is reduced to :
     
20
3
X + 20(1 ÷ 3) + 25(1 ÷ 3) = 4(2 ÷ (2 ÷ 5)) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
    Remove a bracket on the left of the equation:
     
20
3
X + 20 × 1 ÷ 3 + 25(1 ÷ 3) = 4(2 ÷ (2 ÷ 5)) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
    Remove a bracket on the right of the equation::
     
20
3
X + 20 × 1 ÷ 3 + 25(1 ÷ 3) = 4 × 2 ÷ (2 ÷ 5) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
    The equation is reduced to :
     
20
3
X +
20
3
+ 25(1 ÷ 3) = 8 ÷ (2 ÷ 5) + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))
     Multiply both sides of the equation by:(2 ÷ 5)
     
20
3
X (2 ÷ 5) +
20
3
(2 ÷ 5) + 25(1 ÷ 3)(2 ÷ 5) = 8 + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))(2 ÷ 5)
    Remove a bracket on the left of the equation:
     
20
3
X × 2 ÷ 5 +
20
3
(2 ÷ 5) + 25(1 ÷ 3)(2 ÷ 5) = 8 + 3(3)(2 ÷ 3)(2 ÷ (2 ÷ 5))(2 ÷ 5)
    Remove a bracket on the right of the equation::
     
20
3
X × 2 ÷ 5 +
20
3
(2 ÷ 5) + 25(1 ÷ 3)(2 ÷ 5) = 8 + 3 × 3(2 ÷ 3)(2 ÷ (2 ÷ 5))(2 ÷ 5)
    The equation is reduced to :
     
8
3
X +
20
3
(2 ÷ 5) + 25(1 ÷ 3)(2 ÷ 5) = 8 + 9(2 ÷ 3)(2 ÷ (2 ÷ 5))(2 ÷ 5)
    Remove a bracket on the left of the equation:
     
8
3
X +
20
3
× 2 ÷ 5 + 25(1 ÷ 3)(2 ÷ 5) = 8 + 9(2 ÷ 3)(2 ÷ (2 ÷ 5))(2 ÷ 5)
    Remove a bracket on the right of the equation::
     
8
3
X +
20
3
× 2 ÷ 5 + 25(1 ÷ 3)(2 ÷ 5) = 8 + 9 × 2 ÷ 3 × (2 ÷ (2 ÷ 5))(2 ÷ 5)
    The equation is reduced to :
     
8
3
X +
8
3
+ 25(1 ÷ 3)(2 ÷ 5) = 8 + 6(2 ÷ (2 ÷ 5))(2 ÷ 5)
    Remove a bracket on the left of the equation:
     
8
3
X +
8
3
+ 25 × 1 ÷ 3 × (2 ÷ 5) = 8 + 6(2 ÷ (2 ÷ 5))(2 ÷ 5)
    This equation has no real solution!


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