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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/d+1/(d-5)+1/(d-6) = 1/(d-1) .
    Question type: Equation
    Solution:Original question:
     1 ÷ d + 1 ÷ ( d 5) + 1 ÷ ( d 6) = 1 ÷ ( d 1)
     Multiply both sides of the equation by: d  ,  ( d 1)
     1( d 1) + 1 ÷ ( d 5) × d ( d 1) + 1 ÷ ( d 6) × d ( d 1) = 1 d
    Remove a bracket on the left of the equation::
     1 d 1 × 1 + 1 ÷ ( d 5) × d ( d 1) + 1 ÷ ( d 6) × d ( d 1) = 1 d
    The equation is reduced to :
     1 d 1 + 1 ÷ ( d 5) × d ( d 1) + 1 ÷ ( d 6) × d ( d 1) = 1 d
     Multiply both sides of the equation by:( d 5)
     1 d ( d 5)1( d 5) + 1 d ( d 1) + 1 ÷ ( d 6) × d ( d 1) = 1 d ( d 5)
    Remove a bracket on the left of the equation:
     1 d d 1 d × 51( d 5) + 1 d ( d 1) + 1 = 1 d ( d 5)
    Remove a bracket on the right of the equation::
     1 d d 1 d × 51( d 5) + 1 d ( d 1) + 1 = 1 d d 1 d × 5
    The equation is reduced to :
     1 d d 5 d 1( d 5) + 1 d ( d 1) + 1 ÷ ( d 6) = 1 d d 5 d
     Multiply both sides of the equation by:( d 6)
     1 d d ( d 6)5 d ( d 6)1( d 5)( d 6) + 1 d = 1 d d ( d 6)5 d ( d 6)
    Remove a bracket on the left of the equation:
     1 d d d 1 d d × 65 d ( d 6)1 = 1 d d ( d 6)5 d ( d 6)
    Remove a bracket on the right of the equation::
     1 d d d 1 d d × 65 d ( d 6)1 = 1 d d d 1 d d × 65 d ( d 6)
    The equation is reduced to :
     1 d d d 6 d d 5 d ( d 6)1( d 5) = 1 d d d 6 d d 5 d ( d 6)
    Remove a bracket on the left of the equation:
     1 d d d 6 d d 5 d d + 5 d = 1 d d d 6 d d 5 d ( d 6)
    Remove a bracket on the right of the equation::
     1 d d d 6 d d 5 d d + 5 d = 1 d d d 6 d d 5 d d + 5 d
    The equation is reduced to :
     1 d d d 6 d d 5 d d + 30 d = 1 d d d 6 d d 5 d d + 30 d
    Remove a bracket on the left of the equation:
     1 d d d 6 d d 5 d d + 30 d = 1 d d d 6 d d 5 d d + 30 d
    The equation is reduced to :
     1 d d d 6 d d 5 d d + 30 d = 1 d d d 6 d d 5 d d + 30 d
    Remove a bracket on the left of the equation:
     1 d d d 6 d d 5 d d + 30 d = 1 d d d 6 d d 5 d d + 30 d
    The equation is reduced to :
     1 d d d 6 d d 5 d d + 30 d = 1 d d d 6 d d 5 d d + 30 d
    The equation is reduced to :
     1 d d d 6 d d 5 d d + 36 d = 1 d d d 6 d d 5 d d + 30 d
    Remove a bracket on the left of the equation:
     1 d d d 6 d d 5 d d + 36 d = 1 d d d 6 d d 5 d d + 30 d
    The equation is reduced to :
     1 d d d 6 d d 5 d d + 36 d = 1 d d d 6 d d 5 d d + 30 d

    
        d≈5.494940 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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