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    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 90%×[(1+20%)x+(2200-x)×(1+15%)]-2200 = 131 .
    Question type: Equation
    Solution:Original question:
     
90
100
((1 +
20
100
) x + (2200 x )(1 +
15
100
))2200 = 131
    Remove the bracket on the left of the equation:
     Left side of the equation =
90
100
(1 +
20
100
) x +
90
100
(2200 x )(1 +
15
100
)2200
                                             =
90
100
× 1 x +
90
100
×
20
100
x +
90
100
(2200 x )(1 +
15
100
)2200
                                             =
9
10
x +
9
50
x +
90
100
(2200 x )(1 +
15
100
)2200
                                             =
27
25
x +
90
100
(2200 x )(1 +
15
100
)2200
                                             =
27
25
x +
90
100
× 2200(1 +
15
100
)
90
100
x (1 +
15
100
)2200
                                             =
27
25
x + 1980(1 +
15
100
)
90
100
x (1 +
15
100
)2200
                                             =
27
25
x + 1980 × 1 + 1980 ×
15
100
90
100
x (1 +
15
100
)2200
                                             =
27
25
x + 1980 + 297
90
100
x (1 +
15
100
)2200
                                             =
27
25
x + 77
90
100
x (1 +
15
100
)
                                             =
27
25
x + 77
90
100
x × 1
90
100
x ×
15
100
                                             =
27
25
x + 77
9
10
x
27
200
x
                                             =
9
200
x + 77
    The equation is transformed into :
     
9
200
x + 77 = 131

    Transposition :
     
9
200
x = 13177

    Combine the items on the right of the equation:
     
9
200
x = 54

    The coefficient of the unknown number is reduced to 1 :
      x = 54 ÷
9
200
        = 54 ×
200
9
        = 6 × 200

    We obtained :
      x = 1200
    This is the solution of the equation.



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