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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (0.67276/(0.66668/x)+0.65452/(0.66060/x))/2 = x .
    Question type: Equation
    Solution:Original question:
     (
16819
25000
÷ (
16667
25000
÷ x ) +
16363
25000
÷ (
3303
5000
÷ x )) ÷ 2 = x
    Remove a bracket on the left of the equation::
     
16819
25000
÷ (
16667
25000
÷ x ) ÷ 2 +
16363
25000
÷ (
3303
5000
÷ x ) ÷ 2 = x
    The equation is reduced to :
     
16819
50000
÷ (
16667
25000
÷ x ) +
16363
50000
÷ (
3303
5000
÷ x ) = x
     Multiply both sides of the equation by:(
16667
25000
÷ x )
     
16819
50000
+
16363
50000
÷ (
3303
5000
÷ 1) × (
16667
25000
÷ 1) = 1(
16667
25000
÷ 1)
    Remove a bracket on the left of the equation:
     
16819
50000
+
16363
50000
÷ (
3303
5000
÷ 1) ×
16667
25000
÷ 1 = 1(
16667
25000
÷ 1)
    Remove a bracket on the right of the equation::
     
16819
50000
+
16363
50000
÷ (
3303
5000
÷ 1) ×
16667
25000
÷ 1 = 1 ×
16667
25000
÷ 1
    The equation is reduced to :
     
16819
50000
+
272722121
1250000000
÷ (
3303
5000
÷ 1) =
16667
25000
     Multiply both sides of the equation by:(
3303
5000
÷ 1)
     
16819
50000
(
3303
5000
÷ 1) +
272722121
1250000000
=
16667
25000
(
3303
5000
÷ 1)
    Remove a bracket on the left of the equation:
     
16819
50000
×
3303
5000
÷ 1 +
272722121
1250000000
=
16667
25000
(
3303
5000
÷ 1)
    Remove a bracket on the right of the equation::
     
16819
50000
×
3303
5000
÷ 1 +
272722121
1250000000
=
16667
25000
×
3303
5000
÷ 1
    The equation is reduced to :
     
55553157
250000000
+
272722121
1250000000
=
55051101
125000000
    
    There are 0 solution(s).


解程的详细方法请参阅:《方程的解法》



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