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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 0.586*（0.22-k）/(0.22+2*k)+(1-0.586)*(1.262-k)/(1.262+2*k) = 0 .
    Question type: Equation
    Solution:Original question:
     
293
500
(
11
50
 − k ) ÷ (
11
50
 + 2 k ) + (1 −
293
500
)(
631
500
 − k ) ÷ (
631
500
 + 2 k ) = 0
     Multiply both sides of the equation by:(
11
50
 + 2 k )
     
293
500
(
11
50
 − k ) + (1 −
293
500
)(
631
500
 − k ) ÷ (
631
500
 + 2 k ) × (
11
50
 + 2 k ) = 0
    Remove a bracket on the left of the equation:：
     
293
500
 ×
11
50
 −
293
500
 k + (1 −
293
500
)(
631
500
 − k ) ÷ (
631
500
 + 2 k ) × (
11
50
 + 2 k ) = 0
    The equation is reduced to :
     
3223
25000
 −
293
500
 k + (1 −
293
500
)(
631
500
 − k ) ÷ (
631
500
 + 2 k ) × (
11
50
 + 2 k ) = 0
     Multiply both sides of the equation by:(
631
500
 + 2 k )
     
3223
25000
(
631
500
 + 2 k ) −
293
500
 k (
631
500
 + 2 k ) + (1 −
293
500
)(
631
500
 − k )(
11
50
 + 2 k ) = 0
    Remove a bracket on the left of the equation:
     
3223
25000
 ×
631
500
 +
3223
25000
 × 2 k −
293
500
 k (
631
500
 + 2 k ) + (1 −
293
500
)(
631
500
 − k )(
11
50
 + 2 k ) = 0
    The equation is reduced to :
     
2033713
12500000
 +
3223
12500
 k −
293
500
 k (
631
500
 + 2 k ) + (1 −
293
500
)(
631
500
 − k )(
11
50
 + 2 k ) = 0
    Remove a bracket on the left of the equation:
     
2033713
12500000
 +
3223
12500
 k −
293
500
 k ×
631
500
 −
293
500
 k × 2 k + (1 −
293
500
)(
631
500
 − k ) = 0
    The equation is reduced to :
     
2033713
12500000
 +
3223
12500
 k −
184883
250000
 k −
293
250
 k k + (1 −
293
500
)(
631
500
 − k )(
11
50
 + 2 k ) = 0
    The equation is reduced to :
     
2033713
12500000
 −
120423
250000
 k −
293
250
 k k + (1 −
293
500
)(
631
500
 − k )(
11
50
 + 2 k ) = 0
    Remove a bracket on the left of the equation:
     
2033713
12500000
 −
120423
250000
 k −
293
250
 k k + 1(
631
500
 − k )(
11
50
 + 2 k ) −
293
500
(
631
500
 − k )(
11
50
 + 2 k ) = 0
    Remove a bracket on the left of the equation:
     
2033713
12500000
 −
120423
250000
 k −
293
250
 k k + 1 ×
631
500
(
11
50
 + 2 k ) − 1 k (
11
50
 + 2 k ) = 0
    The equation is reduced to :
     
2033713
12500000
 −
120423
250000
 k −
293
250
 k k +
631
500
(
11
50
 + 2 k ) − 1 k (
11
50
 + 2 k ) −
293
500
 = 0
    Remove a bracket on the left of the equation:
     
2033713
12500000
 −
120423
250000
 k −
293
250
 k k +
631
500
 ×
11
50
 +
631
500
 × 2 k − 1 = 0
    The equation is reduced to :
     
2033713
12500000
 −
120423
250000
 k −
293
250
 k k +
6941
25000
 +
631
250
 k − 1 k (
11
50
 + 2 k ) = 0

    The solution of the equation:
        k1≈-0.272796 , keep 6 decimal places
        k2≈0.508878 , keep 6 decimal places    
    There are 2 solution(s).

解程的详细方法请参阅：《方程的解法》


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