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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 12x[1−(1+4%)−(75.21−60)]/4%x(1+4%) = 0 .
    Question type: Equation
    Solution:Original question:
     12 x (1(1 +
4
100
)(
7521
100
60)) ÷
4
100
× x (1 +
4
100
) = 0
     Left side of the equation = 300 x (1(1 +
4
100
)(
7521
100
60)) x (1 +
4
100
)
    The equation is transformed into :
     300 x (1(1 +
4
100
)(
7521
100
60)) x (1 +
4
100
) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = 300 x × 1 x (1 +
4
100
)300 x (1 +
4
100
) x (1 +
4
100
)300 x
                                             = 300 x x (1 +
4
100
)300 x (1 +
4
100
) x (1 +
4
100
)300 x (
7521
100
60)
                                             = 300 x x × 1 + 300 x x ×
4
100
300 x (1 +
4
100
) x
                                             = 300 x x + 12 x x 300 x (1 +
4
100
) x (1 +
4
100
)300
                                             = 300 x x + 12 x x 300 x × 1 x (1 +
4
100
)300
                                             = 300 x x + 12 x x 300 x x (1 +
4
100
)12 x
                                             = 300 x x + 12 x x 300 x x × 1300 x
                                             = 300 x x + 12 x x 300 x x 12 x x
                                             = 300 x x + 12 x x 300 x x 12 x x
                                             = 300 x x + 12 x x 300 x x 12 x x
                                             = 300 x x + 12 x x 300 x x 12 x x
                                             = 300 x x + 12 x x 300 x x 12 x x
                                             = 300 x x + 12 x x 300 x x 12 x x
                                             = 300 x x + 12 x x 300 x x 12 x x
                                             = 300 x x + 12 x x 300 x x 12 x x
                                             = 300 x x + 12 x x 300 x x 12 x x
    The equation is transformed into :
     300 x x + 12 x x 300 x x 12 x x = 0

    After the equation is converted into a general formula, it is converted into:
    ( x - 0 )( x - 0 )=0
    From
        x - 0 = 0
        x - 0 = 0

    it is concluded that::
        x1=0
        x2=0
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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