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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation x+x*(3+2+1.5+10)*0.01+(x+x*(3+2+1.5+10)*0.01)*0.03 = 2655600 .
    Question type: Equation
    Solution:Original question:
      x + x (3 + 2 +
3
2
+ 10) ×
1
100
+ ( x + x (3 + 2 +
3
2
+ 10) ×
1
100
) ×
3
100
= 2655600
    Remove the bracket on the left of the equation:
     Left side of the equation = x + x × 3 ×
1
100
+ x × 2 ×
1
100
+ x ×
3
2
×
1
100
+ x × 10
                                             = x + x ×
3
100
+ x ×
1
50
+ x ×
3
200
+ x ×
1
10
+ ( x + x (3 + 2 +
3
2
+ 10) ×
1
100
) ×
3
100
                                             =
233
200
x + ( x + x (3 + 2 +
3
2
+ 10) ×
1
100
) ×
3
100
                                             =
233
200
x + x ×
3
100
+ x (3 + 2 +
3
2
+ 10) ×
1
100
×
3
100
                                             =
233
200
x + x ×
3
100
+ x (3 + 2 +
3
2
+ 10) ×
3
10000
                                             =
239
200
x + x (3 + 2 +
3
2
+ 10) ×
3
10000
                                             =
239
200
x + x × 3 ×
3
10000
+ x × 2 ×
3
10000
+ x ×
3
2
×
3
10000
+ x
                                             =
239
200
x + x ×
9
10000
+ x ×
3
5000
+ x ×
9
20000
+ x ×
3
1000
                                             =
23999
20000
x
    The equation is transformed into :
     
23999
20000
x = 2655600

    The coefficient of the unknown number is reduced to 1 :
      x = 2655600 ÷
23999
20000
        = 2655600 ×
20000
23999

    We obtained :
      x =
53112000000
23999
    This is the solution of the equation.



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