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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (H*0.5*26+(H*2+0.5)*0.5)*1.2+0.5*3*1.4 = 15 .
    Question type: Equation
    Solution:Original question:
     ( H ×
1
2
× 26 + ( H × 2 +
1
2
) ×
1
2
) ×
6
5
+
1
2
× 3 ×
7
5
= 15
     Left side of the equation = ( H ×
1
2
× 26 + ( H × 2 +
1
2
) ×
1
2
) ×
6
5
+
21
10
    The equation is transformed into :
     ( H ×
1
2
× 26 + ( H × 2 +
1
2
) ×
1
2
) ×
6
5
+
21
10
= 15
    Remove the bracket on the left of the equation:
     Left side of the equation = H ×
1
2
× 26 ×
6
5
+ ( H × 2 +
1
2
) ×
1
2
×
6
5
+
21
10
                                             = H ×
78
5
+ ( H × 2 +
1
2
) ×
3
5
+
21
10
                                             =
78
5
H + H × 2 ×
3
5
+
1
2
×
3
5
+
21
10
                                             =
78
5
H + H ×
6
5
+
3
10
+
21
10
                                             =
84
5
H +
12
5
    The equation is transformed into :
     
84
5
H +
12
5
= 15

    Transposition :
     
84
5
H = 15
12
5

    Combine the items on the right of the equation:
     
84
5
H =
63
5

    The coefficient of the unknown number is reduced to 1 :
      H =
63
5
÷
84
5
        =
63
5
×
5
84
        = 3 ×
1
4

    We obtained :
      H =
3
4
    This is the solution of the equation.

    Convert the result to decimal form :
      H = 0.75



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