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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation ((2000-x)/4+300)(1+2(2000-x)/1400) = x .
    Question type: Equation
    Solution:Original question:
     ((2000 x ) ÷ 4 + 300)(1 + 2(2000 x ) ÷ 1400) = x
    Remove the bracket on the left of the equation:
     Left side of the equation = (2000 x ) ÷ 4 × (1 + 2(2000 x ) ÷ 1400) + 300(1 + 2(2000 x ) ÷ 1400)
                                             = 2000 ×
1
4
(1 + 2(2000 x ) ÷ 1400) x ×
1
4
(1 + 2(2000 x ) ÷ 1400) + 300(1 + 2(2000 x ) ÷ 1400)
                                             = 500(1 + 2(2000 x ) ÷ 1400) x ×
1
4
(1 + 2(2000 x ) ÷ 1400) + 300(1 + 2(2000 x ) ÷ 1400)
                                             = 500 × 1 + 500 × 2(2000 x ) ÷ 1400 x ×
1
4
(1 + 2(2000 x ) ÷ 1400) + 300(1 + 2(2000 x ) ÷ 1400)
                                             = 500 +
5
7
(2000 x ) x ×
1
4
(1 + 2(2000 x ) ÷ 1400) + 300(1 + 2(2000 x ) ÷ 1400)
                                             = 500 +
5
7
× 2000
5
7
x x ×
1
4
(1 + 2(2000 x ) ÷ 1400) + 300(1 + 2(2000 x ) ÷ 1400)
                                             = 500 +
10000
7
5
7
x x ×
1
4
(1 + 2(2000 x ) ÷ 1400) + 300(1 + 2(2000 x ) ÷ 1400)
                                             =
13500
7
5
7
x x ×
1
4
(1 + 2(2000 x ) ÷ 1400) + 300(1 + 2(2000 x ) ÷ 1400)
                                             =
13500
7
5
7
x x ×
1
4
× 1 x ×
1
4
× 2(2000 x ) ÷ 1400 + 300
                                             =
13500
7
5
7
x x ×
1
4
x ×
1
2800
(2000 x ) + 300(1 + 2(2000 x ) ÷ 1400)
                                             =
13500
7
27
28
x x ×
1
2800
(2000 x ) + 300(1 + 2(2000 x ) ÷ 1400)
                                             =
13500
7
27
28
x x ×
1
2800
× 2000 + x ×
1
2800
x + 300(1 + 2(2000 x ) ÷ 1400)
                                             =
13500
7
27
28
x x ×
5
7
+ x ×
1
2800
x + 300(1 + 2(2000 x ) ÷ 1400)
                                             =
13500
7
47
28
x + x ×
1
2800
x + 300(1 + 2(2000 x ) ÷ 1400)
                                             =
13500
7
47
28
x + x ×
1
2800
x + 300 × 1 + 300 × 2(2000 x ) ÷ 1400
                                             =
13500
7
47
28
x + x ×
1
2800
x + 300 +
3
7
(2000 x )
                                             =
15600
7
47
28
x + x ×
1
2800
x +
3
7
(2000 x )
                                             =
15600
7
47
28
x + x ×
1
2800
x +
3
7
× 2000
3
7
x
                                             =
15600
7
47
28
x + x ×
1
2800
x +
6000
7
3
7
x
                                             =
21600
7
59
28
x + x ×
1
2800
x
    The equation is transformed into :
     
21600
7
59
28
x + x ×
1
2800
x = x

    
        x≈1143.366251 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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