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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation ((3000-x)×0.3+300)(1+2(3000-x)/21000) = x-0.05×3000 .
    Question type: Equation
    Solution:Original question:
     ((3000 x ) ×
3
10
+ 300)(1 + 2(3000 x ) ÷ 21000) = x
1
20
× 3000
    Remove the bracket on the left of the equation:
     Left side of the equation = (3000 x ) ×
3
10
(1 + 2(3000 x ) ÷ 21000) + 300(1 + 2(3000 x ) ÷ 21000)
                                             = 3000 ×
3
10
(1 + 2(3000 x ) ÷ 21000) x ×
3
10
(1 + 2(3000 x ) ÷ 21000) + 300(1 + 2(3000 x ) ÷ 21000)
                                             = 900(1 + 2(3000 x ) ÷ 21000) x ×
3
10
(1 + 2(3000 x ) ÷ 21000) + 300(1 + 2(3000 x ) ÷ 21000)
                                             = 900 × 1 + 900 × 2(3000 x ) ÷ 21000 x ×
3
10
(1 + 2(3000 x ) ÷ 21000) + 300(1 + 2(3000 x ) ÷ 21000)
                                             = 900 +
3
35
(3000 x ) x ×
3
10
(1 + 2(3000 x ) ÷ 21000) + 300(1 + 2(3000 x ) ÷ 21000)
                                             = 900 +
3
35
× 3000
3
35
x x ×
3
10
(1 + 2(3000 x ) ÷ 21000) + 300(1 + 2(3000 x ) ÷ 21000)
                                             = 900 +
1800
7
3
35
x x ×
3
10
(1 + 2(3000 x ) ÷ 21000) + 300(1 + 2(3000 x ) ÷ 21000)
                                             =
8100
7
3
35
x x ×
3
10
(1 + 2(3000 x ) ÷ 21000) + 300(1 + 2(3000 x ) ÷ 21000)
                                             =
8100
7
3
35
x x ×
3
10
× 1 x ×
3
10
× 2(3000 x ) ÷ 21000 + 300
                                             =
8100
7
3
35
x x ×
3
10
x ×
1
35000
(3000 x ) + 300(1 + 2(3000 x ) ÷ 21000)
                                             =
8100
7
27
70
x x ×
1
35000
(3000 x ) + 300(1 + 2(3000 x ) ÷ 21000)
                                             =
8100
7
27
70
x x ×
1
35000
× 3000 + x ×
1
35000
x + 300(1 + 2(3000 x ) ÷ 21000)
                                             =
8100
7
27
70
x x ×
3
35
+ x ×
1
35000
x + 300(1 + 2(3000 x ) ÷ 21000)
                                             =
8100
7
33
70
x + x ×
1
35000
x + 300(1 + 2(3000 x ) ÷ 21000)
                                             =
8100
7
33
70
x + x ×
1
35000
x + 300 × 1 + 300 × 2(3000 x ) ÷ 21000
                                             =
8100
7
33
70
x + x ×
1
35000
x + 300 +
1
35
(3000 x )
                                             =
10200
7
33
70
x + x ×
1
35000
x +
1
35
(3000 x )
                                             =
10200
7
33
70
x + x ×
1
35000
x +
1
35
× 3000
1
35
x
                                             =
10200
7
33
70
x + x ×
1
35000
x +
600
7
1
35
x
                                             =
10800
7
1
2
x + x ×
1
35000
x
    The equation is transformed into :
     
10800
7
1
2
x + x ×
1
35000
x = x
1
20
× 3000
     Right side of the equation = x 150
    The equation is transformed into :
     
10800
7
1
2
x + x ×
1
35000
x = x 150

    
        x≈1153.934571 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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