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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (60×80)/2-20a/2 = 60×60-(60-a)×60/2 .
    Question type: Equation
    Solution:Original question:
     (60 × 80) ÷ 220 a ÷ 2 = 60 × 60(60 a ) × 60 ÷ 2
     Left side of the equation = (60 × 80) ×
1
2
10 a
    The equation is transformed into :
     (60 × 80) ×
1
2
10 a = 60 × 60(60 a ) × 60 ÷ 2
    Remove the bracket on the left of the equation:
     Left side of the equation = 60 × 80 ×
1
2
10 a
                                             = 240010 a
    The equation is transformed into :
     240010 a = 60 × 60(60 a ) × 60 ÷ 2
     Right side of the equation = 3600(60 a ) × 30
    The equation is transformed into :
     240010 a = 3600(60 a ) × 30
    Remove the bracket on the right of the equation:
     Right side of the equation = 360060 × 30 + a × 30
                                               = 36001800 + a × 30
                                               = 1800 + 30 a
    The equation is transformed into :
     240010 a = 1800 + 30 a

    Transposition :
      - 10 a 30 a = 18002400

    Combine the items on the left of the equation:
      - 40 a = 18002400

    Combine the items on the right of the equation:
      - 40 a = - 600

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     600 = 40 a

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     40 a = 600

    The coefficient of the unknown number is reduced to 1 :
      a = 600 ÷ 40
        = 600 ×
1
40
        = 15 × 1

    We obtained :
      a = 15
    This is the solution of the equation.



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