Mathematics
         
语言：中文    Language:English
                                Equations   
Fold
                                Unary equation
                                Multivariate equation
                                Math OP  
Unfold
                                Linear algebra      
Unfold
                                Derivative function
                                Function image
                                Hot issues
On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 135.29/(1+(x/12*6))+0.39/(1+x) = 128 .
    Question type: Equation
    Solution:Original question:
     
13529
100
 ÷ (1 + ( x ÷ 12 × 6)) +
39
100
 ÷ (1 + x ) = 128
     Multiply both sides of the equation by:(1 + ( x ÷ 12 × 6))
     
13529
100
 +
39
100
 ÷ (1 + x ) × (1 + ( x ÷ 12 × 6)) = 128(1 + ( x ÷ 12 × 6))
    Remove a bracket on the left of the equation:：
     
13529
100
 +
39
100
 ÷ (1 + x ) × 1 +
39
100
 ÷ (1 + x ) × ( x ÷ 12 × 6) = 128(1 + ( x ÷ 12 × 6))
    Remove a bracket on the right of the equation:：
     
13529
100
 +
39
100
 ÷ (1 + x ) × 1 +
39
100
 ÷ (1 + x ) × ( x ÷ 12 × 6) = 128 × 1 + 128( x ÷ 12 × 6)
    The equation is reduced to :
     
13529
100
 +
39
100
 ÷ (1 + x ) +
39
100
 ÷ (1 + x ) × ( x ÷ 12 × 6) = 128 + 128( x ÷ 12 × 6)
     Multiply both sides of the equation by:(1 + x )
     
13529
100
(1 + x ) +
39
100
 +
39
100
( x ÷ 12 × 6) = 128(1 + x ) + 128( x ÷ 12 × 6)(1 + x )
    Remove a bracket on the left of the equation:
     
13529
100
 × 1 +
13529
100
 x +
39
100
 +
39
100
( x ÷ 12 × 6) = 128(1 + x ) + 128( x ÷ 12 × 6)(1 + x )
    Remove a bracket on the right of the equation:：
     
13529
100
 × 1 +
13529
100
 x +
39
100
 +
39
100
( x ÷ 12 × 6) = 128 × 1 + 128 x + 128( x ÷ 12 × 6)(1 + x )
    The equation is reduced to :
     
13529
100
 +
13529
100
 x +
39
100
 +
39
100
( x ÷ 12 × 6) = 128 + 128 x + 128( x ÷ 12 × 6)(1 + x )
    The equation is reduced to :
     
3392
25
 +
13529
100
 x +
39
100
( x ÷ 12 × 6) = 128 + 128 x + 128( x ÷ 12 × 6)(1 + x )
    Remove a bracket on the left of the equation:
     
3392
25
 +
13529
100
 x +
39
100
 x ÷ 12 × 6 = 128 + 128 x + 128( x ÷ 12 × 6)(1 + x )
    Remove a bracket on the right of the equation:：
     
3392
25
 +
13529
100
 x +
39
100
 x ÷ 12 × 6 = 128 + 128 x + 128 x ÷ 12 × 6(1 + x )
    The equation is reduced to :
     
3392
25
 +
13529
100
 x +
39
200
 x = 128 + 128 x + 64 x (1 + x )
    The equation is reduced to :
     
3392
25
 +
27097
200
 x = 128 + 128 x + 64 x (1 + x )
    Remove a bracket on the right of the equation:：
     
3392
25
 +
27097
200
 x = 128 + 128 x + 64 x × 1 + 64 x x
    The equation is reduced to :
     
3392
25
 +
27097
200
 x = 128 + 128 x + 64 x + 64 x x
    The equation is reduced to :
     
3392
25
 +
27097
200
 x = 128 + 192 x + 64 x x

    
        x≈0.119674 , keep 6 decimal places    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》


Your problem has not been solved here? Please go to the Hot Problems section！


Return



  New addition:Lenders ToolBox module（Specific location：Math OP > Lenders ToolBox ），welcome。