Mathematics
         
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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 3 questions will be solved this time.Among them
           ☆3 equations

[ 1/3 Equation]
    Work: Find the solution of equation X1+X2+2X3-X4 = 0 .
    Question type: Equation
    Solution:Original question:
      X × 1 + X × 2 + 2 X × 3 X × 4 = 0
     Left side of the equation = X × 1 + X × 2 + 6 X X × 4
                                             = 5 X
    The equation is transformed into :
     5 X = 0

    The coefficient of the unknown number is reduced to 1 :
      X = 0 ÷ 5
        = 0 ×
1
5

    We obtained :
      X = 0
    This is the solution of the equation.

[ 2/3 Equation]
    Work: Find the solution of equation 2X1+X2+X3-X4 = 0 .
    Question type: Equation
    Solution:Original question:
     2 X × 1 + X × 2 + X × 3 X × 4 = 0
     Left side of the equation = 2 X + X × 2 + X × 3 X × 4
                                             = 3 X
    The equation is transformed into :
     3 X = 0

    The coefficient of the unknown number is reduced to 1 :
      X = 0 ÷ 3
        = 0 ×
1
3

    We obtained :
      X = 0
    This is the solution of the equation.

[ 3/3 Equation]
    Work: Find the solution of equation 2X1+2X2+X3+2X4 = 0 .
    Question type: Equation
    Solution:Original question:
     2 X × 1 + 2 X × 2 + X × 3 + 2 X × 4 = 0
     Left side of the equation = 2 X + 4 X + X × 3 + 8 X
                                             = 17 X
    The equation is transformed into :
     17 X = 0

    The coefficient of the unknown number is reduced to 1 :
      X = 0 ÷ 17
        = 0 ×
1
17

    We obtained :
      X = 0
    This is the solution of the equation.



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