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On line Solution of Monovariate Equation：
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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation -0.5（x+3）（4.5-0.5xx）-0.5（2-x）（2-0.5xx）+（6.5-xx）*2.5 = 5 .
    Question type: Equation
    Solution:Original question:
      -
1
2
( x + 3)(
9
2
 −
1
2
 x x ) −
1
2
(2 − x )(2 −
1
2
 x x ) + (
13
2
 − x x ) ×
5
2
 = 5
    Remove the bracket on the left of the equation:
     Left side of the equation = -
1
2
 x (
9
2
 −
1
2
 x x ) −
1
2
 × 3(
9
2
 −
1
2
 x x ) −
1
2
(2 − x )(2 −
1
2
 x x ) + (
13
2
 − x x ) ×
5
2
                                             = -
1
2
 x (
9
2
 −
1
2
 x x ) −
3
2
(
9
2
 −
1
2
 x x ) −
1
2
(2 − x )(2 −
1
2
 x x ) + (
13
2
 − x x ) ×
5
2
                                             = -
1
2
 x ×
9
2
 +
1
2
 x ×
1
2
 x x −
3
2
(
9
2
 −
1
2
 x x ) −
1
2
(2 − x )
                                             = -
9
4
 x +
1
4
 x x x −
3
2
(
9
2
 −
1
2
 x x ) −
1
2
(2 − x )(2 −
1
2
 x x ) + (
13
2
 − x x )
                                             = -
9
4
 x +
1
4
 x x x −
3
2
 ×
9
2
 +
3
2
 ×
1
2
 x x
                                             = -
9
4
 x +
1
4
 x x x −
27
4
 +
3
4
 x x −
1
2
(2 − x )
                                             = -
9
4
 x +
1
4
 x x x −
27
4
 +
3
4
 x x −
1
2
 × 2
                                             = -
9
4
 x +
1
4
 x x x −
27
4
 +
3
4
 x x − 1(2 −
1
2
 x x )
                                             = -
9
4
 x +
1
4
 x x x −
27
4
 +
3
4
 x x − 1 × 2
                                             = -
9
4
 x +
1
4
 x x x −
27
4
 +
3
4
 x x − 2 +
1
2
                                             = -
9
4
 x +
1
4
 x x x −
35
4
 +
3
4
 x x +
1
2
 x
                                             = -
9
4
 x +
1
4
 x x x −
35
4
 +
3
4
 x x +
1
2
 x
                                             = -
9
4
 x +
1
4
 x x x −
35
4
 +
3
4
 x x +
1
2
 x
                                             = -
5
4
 x +
1
4
 x x x −
35
4
 +
3
4
 x x +
1
2
 x
                                             = -
5
4
 x +
1
4
 x x x −
35
4
 +
3
4
 x x +
1
2
 x
                                             = -
5
4
 x +
1
4
 x x x −
35
4
 +
3
4
 x x +
1
2
 x
                                             = -
5
4
 x +
1
4
 x x x +
15
2
 +
3
4
 x x +
1
2
 x
    The equation is transformed into :
      -
5
4
 x +
1
4
 x x x +
15
2
 +
3
4
 x x +
1
2
 x = 5

    After the equation is converted into a general formula, it is converted into:
    ( x + 2 )( x - 1 )=0
    From
        x + 2 = 0
        x - 1 = 0
    it is concluded that:：
        x1=-2
        x2=1    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》


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