Mathematics
         
语言:中文    Language:English
                                Equations   
Fold
                                Unary equation
                                Multivariate equation
                                Math OP  
Unfold
                                Linear algebra      
Unfold
                                Derivative function
                                Function image
                                Hot issues
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (x-12)*(60+8*20-x/2) = 432 .
    Question type: Equation
    Solution:Original question:
     ( x 12)(60 + 8 × 20 x ÷ 2) = 432
    Remove the bracket on the left of the equation:
     Left side of the equation = x (60 + 8 × 20 x ÷ 2)12(60 + 8 × 20 x ÷ 2)
                                             = x × 60 + x × 8 × 20 x x ÷ 212(60 + 8 × 20 x ÷ 2)
                                             = x × 60 + x × 160 x x ×
1
2
12(60 + 8 × 20 x ÷ 2)
                                             = 220 x x x ×
1
2
12(60 + 8 × 20 x ÷ 2)
                                             = 220 x x x ×
1
2
12 × 6012 × 8 × 20 + 12 x
                                             = 220 x x x ×
1
2
7201920 + 6 x
                                             = 226 x x x ×
1
2
2640
    The equation is transformed into :
     226 x x x ×
1
2
2640 = 432

    
        x≈14.028304 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。